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3 years ago

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PLEASE HELP FAST The object distance for a convex lens is 15.0 cm, and the image distance is 5.0 cm. The height of the object is

9.0 cm. What is the height of the image?

1 answer:

IgorLugansk [536]3 years ago

4 0

Answer:

The image height is 3.0 cm

Explanation:

Given;

object distance, $d_o$ = 15.0 cm

image distance, $d_i$ = 5.0 cm

height of the object, $h_o$ = 9.0 cm

height of the image, $h_i$ = ?

Apply lens equation;

$\frac{h_i}{h_o} = -\frac{d_i}{d_o}\\\\ h_i = h_o(-\frac{d_i}{d_o})\\\\h_i = -9(\frac{5}{15} )\\\\h_i = -3 \ cm$

Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.

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Answer:

Free body diagram

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It can be via contact or without contact. Such non-contact forces acts via a force field.

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3 years ago

Suppose we could shrink the Earth without changing its mass. At what fraction of its current radius would the free-fall accelera

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Answer:

$R' = \frac{1}{\sqrt{3}}R$

Explanation:

The acceleration due to gravity on the surface of the Earth is given by:

$g=\frac{GM}{R^2}$

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Here we want to find the new Earth radius R' for which the gravitational acceleration at the surface, g', would be 3 times the current value of g:

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So we would have

$\frac{GM}{R'^2}=3(\frac{GM}{R^2})$

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3 years ago

Read 2 more answers

A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity

WARRIOR [948]

Answer:

The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg

Explanation:

From the formulae

F = qvB and F = mv²/r

Where F is Force

q is charge

v is speed

B is magnetic field strength

m is mass

and r is radius

Then,

qvB = mv²/r

qB = mv/r

We can write that

q/m = v/rB ---- (1)

Also

From Electric force formula

F = Eq

Where E is the electric field

and magnetic force formula

F = Bqv

Since, electric force = magnetic force

Then, Eq = Bqv

E = Bv

∴ v = E/B

Substitute v = E/B into equation (1)

q/m = (E/B)/rB

∴ q/m = E/rB²

(NOTE: q/m is the charge to mass ratio)

From the question,

E = 3.10 ×10³ N/C

r = 4.20 cm = 0.0420 m

B = 0.360 T

Hence,

q/m = 3.10 ×10³ / 0.0420 × (0.360)²

q/m = 569517.9306 C/kg

q/m = 5.7 × 10⁵ C/kg

Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.

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3 years ago

When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

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Explanation:

Given

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Racquet imparts an impulse to the ball which is given by

$J=F\Delta t=\Delta P$

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$m=\frac{540\times 5\times 10^{-3}}{45}$

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4 years ago

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pentagon [3]

Answer:

$\tau_a = F a sin \theta$

Explanation:

The torque of a force is given by:

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where

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In this problem, we have:

$F$ , the force

$a$ , the distance of application of the force from the centre (0,0)

$\theta$ , the angle between the direction of the force and a

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$\tau_a = F a sin \theta$

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