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Anastasy [175]
3 years ago
12

PLEASE HELP FAST The object distance for a convex lens is 15.0 cm, and the image distance is 5.0 cm. The height of the object is

9.0 cm. What is the height of the image?
Physics
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:

The image height is 3.0 cm

Explanation:

Given;

object distance, d_o = 15.0 cm

image distance, d_i = 5.0 cm

height of the object, h_o = 9.0 cm

height of the image, h_i = ?

Apply lens equation;

\frac{h_i}{h_o} = -\frac{d_i}{d_o}\\\\ h_i = h_o(-\frac{d_i}{d_o})\\\\h_i = -9(\frac{5}{15} )\\\\h_i = -3 \ cm

Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.

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The ratio of the lift force L to the drag force D for the simple airfoil is L/D = 10. If the lift force on a short section of th
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Answer:

R=64.32\ lb\\\\\theta=84.3\°

Explanation:

Given:

Ratio of lift force to drag force is, \frac{L}{D}=10

Lift force on a short section is, L=64\ lb

Magnitude of resultant, R= ?

The angle of 'R' with the horizontal is, \theta=?

We know that, lift force and drag are at right angles to each other. So, the resultant can be computed using Pythagoras theorem.

For calculating 'R', we first compute drag force 'D'.

As per question:

\frac{L}{D}=10\\\\D=\frac{L}{10}=\frac{64\ lb}{10}=6.4\ lb

Now, the magnitude of resultant 'R' is given as:

R=\sqrt{L^2+D^2}

Plug in the given values and solve for 'R'. This gives,

R=\sqrt{64^2+6.4^2}\\\\R=\sqrt{4096+40.96}\\\\R=\sqrt{4136.96}=64.32\ lb

Therefore, the magnitude of the resultant force 'R' is 64.32 lb.

Now, the angle \theta is given as the arctan of the ratio of the lift and drag force.

Therefore,

\theta=\tan^{-1}(L/D)\\\\\theta=\tan^{-1}(10)\\\\\theta=84.3\°

Therefore, the angle made with the horizontal is 84.3°.

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3 years ago
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Answer:.

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A 12.0 g bullet was fired horizontally into a 1 kg block of wood. The bullet initially had a speed of 250 m/s. The block of wood
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Answer:

The rise in height of combined block/bullet from its original position is 0.45m

Explanation:

Given;

mass of bullet, m₁ = 12 g = 0.012 kg

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initial speed of bullet, u₁ = 250 m/s.

initial speed of block of wood, u₂ = 0

From the principle of conservation of linear momentum, calculate the final speed of the combined block/bullet system.

m₁u₁ + m₂u₂ = v(m₁+m₂)

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v is the final speed of the combined block/bullet system.

0.012 x 250 + 0 = v (0.012 + 1)

3 = v (1.012)

v = 3/1.012

v = 2.96 m/s

From the principle of conservation of energy, calculate the rise in height of the block/bullet combined from its original position.

¹/₂mv² = mgh

¹/₂v² = gh

¹/₂ (2.96)² = (9.8)h

4.3808 = 9.8h

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Therefore, the rise in height of combined block/bullet from its original position is 0.45m

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