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3 years ago

The density of gold is 19 300kg/m cube. what is the mass of gold cube with the length 0.2015m?

Physics

1 answer:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

157.9 kg

Explanation:

Density: This can be defined as the ratio of the mass of a body and it's volume.

The S.I unit of density is kg/m³.

From the question,

Density = Mass/volume

D = m/v............................ Equation 1

Where D = Density of gold, m = mass of gold, v = volume of gold.

make m the subject of the equation

m = Dv.................... Equation 2

Since the gold is a cube,

v = l³................... Equation 3

Where l = length of the gold cube.

Substitute equation 3 into equation 2

m = Dl³............... Equation 4

Given: D = 19300 kg/m³, l = 0.2015 m

Substitute into equation 4

m = 19300(0.2015)³

m = 157.9 kg.

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Here

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$a_g = \frac{G}{R^2}(\frac{4}{3}\pi R^3)\rho$

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At the same time the general expression for the centripetal acceleration is

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Using this expression in the left hand side of the equation we have that

$\frac{\Theta^2}{R} = \frac{4}{3}G\pi \rho R^2$

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$\Theta = (\frac{4}{3}G\pi \rho)^{1/2}R$

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vivado [14]

Answer:

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F= μη

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μ is the coefficient of static friction.

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julsineya [31]

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<u>Explanation:</u>

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lina2011 [118]

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Side note:
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