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padilas [110]
3 years ago
8

A model rocket is launched straight upward with an initial speed of 56.5 m/s. It accelerates with a constant upward acceleration

of 1.96 m/s 2 until its engines stop at an altitude of 198.8 m. What is the maximum height reached by the rocket? Answer in units of m.
Physics
1 answer:
marta [7]3 years ago
3 0

Answer:

Maximum height reached by the rocket, h = 202.62 meters            

Explanation:

It is given that,

Initial speed of the model rocket, u = 56.5 m/s

Constant upward acceleration, a=1.96\ m/s^2

Distance traveled by the engine until it stops, d = 198.8 m

Let v is the speed of the rocket when the engine stops. It can be calculated using the third equation of motion as :

v=\sqrt{u^2+2ad}

v=\sqrt{(56.5)^2+2\times 1.96\times 198.8}    

v = 63.02 m/s

At the maximum height, v = 0 and the engine now decelerate under the action of gravity, a = -g. Let h is the maximum height reached by the rocket.

Again using third equation of motion as :

v^2-u^2=-2gh

h=\dfrac{v^2-u^2}{-2g}

h=\dfrac{u^2}{2g}

h=\dfrac{(63.02)^2}{2\times 9.8}

h = 202.62 meters

So, the maximum height reached by the rocket is 202.62 meters. Hence, this is the required solution.

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