Saturn's rings are made of billions of pieces of ice, dust and rocks. Some of these particles are as small as a grain of salt, while others are as big as houses.
Answer:
20.4e18 electrons/second ≈ 2e19 electrons/second
Explanation:
Hi!
To solve this problem we are going to use Omh's Law:
V = RI
And the relation ship between the resistance R and conductivity:
R = L/(σA)
*here we are considering a omhic material*
The conductance σ is related to electron mobility and electron density by:
σ = nμ
Replacing all these relations in the omhs law, we get:
V = (LI)/(σA)
We know that both wire are subject to the same electric field, therefore V is the same for both, moreover, since no additional info for the length of the wires is given we are going to consider that L is the same for both. Therefore
This means that:
From the relation of the conductance and electron mobility and density, and the data given to us, we know that:
Also
Therefore:
That is:
Since I_A = 3*10^18 e/s
I_B = 20.4*10^18 e/s
A.
Kinematics is independent of mass, in most cases.
Answer:
1).
2). Toward us
3).
4). Toward us
5).
6). Away from us
7).
8). Away from us
Explanation:
Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when it is moving away from the observer (that is known as the Doppler effect).
The wavelength at rest is 121.6 nm ()
Then, for this particular case it is gotten:
Star 1:
Star 2:
Star 3:
Star 4:
Star 1:
Toward us
Star 2:
Toward us
Star 3:
Away from us
Star 4:
Away from us
Due to that shift the velocity of the star can be determine by means of Doppler velocity.
(1)
Where is the wavelength shift, is the wavelength at rest, v is the velocity of the source and c is the speed of light.
(2)
<em>Case for star 1 :</em>
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Notice that the negative velocity means that is approaching to the observer.
<em>Case for star 2 :</em>
<em>Case for star 3 :</em>
<em>Case for star 4 :</em>