Hi! I believe the answer is 2 meters(:
Answer:
From the main bearings, the oil passes through feed-holes into drilled passages in the crankshaft and on to the big-end bearings of the connecting rod.
Answer:
the rate of heat loss from the steam turbine is Q = 200 kW
Explanation:
From the first law of thermodynamics applied to open systems
Q-W₀ = F*(ΔH + ΔK + ΔV)
where
Q= heat loss
W₀= power generated by the turbine
F= mass flow
ΔH = enthalpy change
ΔK = kinetic energy change
ΔV = potencial energy change
If we neglect the changes in potential and kinetic energy compared with the change in enthalpy , then
Q-W₀ = F*ΔH
Q = F*ΔH+ W₀
replacing values
Q = F*ΔH+ W₀ = 420 kg/min * (-600 kJ/kg) * 1 min/60 s * 1 MW/1000 kW + 4 MW = -0.2 MW = -200 kW (negative sign comes from outflow of energy)
Answer:
when you are in the design process so you can get his insite
Explanation:
Answer:
116 ft/s
Explanation:
D = 0.10x² – 3.00x + 22.0
1019.50 = 0.10x² – 3.00x + 22.0
0 = 0.10x² – 3.00x – 997.5
0 = x² – 30x – 9975
Solve with quadratic formula:
x = [ -(-30) ± √((-30)² − 4(1)(-9975)) ] / 2(1)
x = [ 30 ± √(900 + 39900) ] / 2
x = (30 ± 20√102) / 2
x = 15 ± 10√102
x ≈ 116