The average velocity can be calculated using the formula:
v = d / t
For the 1st car, the velocity is calculated
as:
v1 = 8.60 m / 1.80 s = 4.78 m / s
While that of the 2nd car is:
v2 = 8.60 m / 1.66 s = 5.18 m / s
Now we can solve for the acceleration using the formula:
v2^2 = v1^2 + 2 a d
Rewriting in terms of a:
a = (v2^2 – v1^2) / 2 d
a = (5.18^2 – 4.78^2) / (2 * 8.6)
a = 0.23 m/s
Therefore the train has a constant acceleration of about
0.23 meters per second.
Answer: if 5N is applied for 5 seconds then it would move at a constant speed for one second then decrease in speed
Answer:
While a body is said to be in motion if it changes its position with respect to immediate surroundings.
A body is said to be in uniform motion if it covers equal distances in equal interval of time.
A body is said to be in non-uniform motion if it covers unequal distances in equal interval of time or vice-versa
Answer:
Explanation:
Positive values for position indicate that the object is in front of the starting point and negative values tell us that the object is behind the starting point. (time = 9.5, position = 0) the object is at the starting point.
Answer: Force and Movement
Explanation:
The first is that the object moves. The second is that a force must act on the object in the direction the object moves.