Answer:
are produces are in a month.
Explanation:
Quantity of eggs produced by the chicken in a month = 284 dozens
1 dozen = 12 eggs
Number of eggs in a month:

are produces are in a month.
<span>0.48 grams.
Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced.
To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So
0.0075 mol * 63.546 g/mol = 0.476595 g.
Round the results to 2 significant figures, giving 0.48 grams.</span>
Answer : The percent purity of
in the original sample is 87.94 %
Explanation :
The given balanced chemical reaction is:

First we have to calculate the mass of Fe.

Molar mass of Fe = 55.8 g/mole

Now we have to calculate the moles of 
From the balanced chemical reaction we conclude that,
As, 2 moles of Fe produced from 1 mole of 
So,
of Fe produced from
mole of 
Now we have to calculate the mass of 

Molar mass of
= 159.69 g/mole

Now we have to calculate the percent purity of
in the original sample.
Mass of original sample = 


Therefore, the percent purity of
in the original sample is 87.94 %
Answer:
( About ) 0.03232 M
Explanation:
Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [
]"
This formula would be true for the following information -
{
= the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }
________
Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6
1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X
1 / [X] = 28.8 + 1 / ( 0.467 ),
1 / [X] = 28.8 + 2.1413...,
1 / [X] = 31,
[X] = 1 / 31 = ( About ) 0.03232 M
Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M
This statement explains that jelly fish in an endemic species