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Zinaida [17]
3 years ago
6

Write the net ionic equation to show the formation of a precipitate (insoluble salt) when the following solutions are mixed. Wri

te none if no insoluble salt forms. (12.3)
a.Pb(NO3)2(aq) + NaBr(aq)
Chemistry
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer:

Pb²⁺(aq) + 2Br⁻(aq) ⟶ PbBr₂(s)  

Explanation:

A. Molecular equation

Pb(NO₃)₂(aq) + 2NaBr(aq) ⟶ PbBr₂(?) + 2NaNO₃(?)

To predict whether there is a precipitate, we must remember some solubility rules:

  1. Salts containing Na⁺ are soluble  
  2. Salts containing Br⁻ are generally soluble. An important exception to this rule is that PbBr₂ is insoluble.

Thus, the molecular equation is

Pb(NO₃)₂(aq) + 2NaBr(aq) ⟶ PbBr₂(s) + 2NaNO₃(aq)

B. Ionic equation

We write all the soluble substances as ions.

Pb²⁺(aq) + 2NO₃⁻(aq) + 2Na⁺(aq) + 2Br⁻(aq) ⟶ PbBr₂(s) + 2Na⁺(aq) + 2NO₃⁻(aq)

C. Net ionic equation

To get the net ionic equation, we cancel the ions that appear on each side of the ionic equation.

Pb²⁺(aq) + <u>2NO₃⁻(aq)</u> + <u>2Na⁺(aq)</u> + 2Br⁻(aq) ⟶ PbBr₂(s) + <u>2Na⁺(aq)</u> + <u>2NO₃⁻(aq) </u>

The net ionic equation is

Pb²⁺(aq) + 2Br⁻(aq) ⟶ PbBr₂(s)

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35.0 grams of nitrogen gas reacts with 60.0 grams of hydrogen gas: N2 + 3H2--&gt; 2NH3
Misha Larkins [42]

Explanation:

Moles of N2 = 35.0g / (28g/mol) = 1.25mol

Moles of H2 = 60.0g / (2g/mol) = 30.0mol

Since 1.25mol * 3 < 30.0mol, nitrogen is limiting.

Moles of NH3 = 1.25mol * 2 = 2.50mol.

Mass of NH3 = 2.50mol * (17g/mol) = 42.5g.

30.0mol - 1.25mol * 3 = 26.25mol.

Excess mass of H2

= 26.25mol * (2g/mol) = 52.5g.

6 0
3 years ago
In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 gram
kherson [118]

This question is incomplete, the complete question is;

In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 grams. If the % composition of the acetanilide impurity in the sample is 6.3 %, what is the minimum amount in mL of solvent (water) required for the recrystallization

Compound      Solubility in water at 25°C      Solubility in water at 100°C

Benzoic Acid      0.34 g/100mL                           5.6 g/100mL

Acetanilide         0.53 g/100mL                           5.5 g/100mL

Answer:

The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL

Explanation:

Given the data in the question;

mass of sample = 5 g

percentage composition of the acetanilide impurity = 6.3%

mass of the acetanilide in impure sample will be;

⇒ 6.3% × 5 g = 0.315 g

Mass of benzoic acid in impure sample;

⇒ 5 g - 0.315 g = 4.685 g

now, solubility in water at 100°C for benzoic acid = 5.6 g/100mL

hence 4.685 g of benzoic acid is soluble in x mL

x = [ 100 mL × 4.685 g ] / 5.6 g

x = 83.66 ≈ 84 mL

Also, solubility in water at 100°C for acetanilide = 5.5 g/100mL

hence 0.315 g of benzoic acid is soluble in x mL

x = [ 100 mL × 0.315 g ] / 5.5 g

x = 5.727 ≈ 6 mL

So, the minimum amount in mL of solvent (water) required for the recrystallization will be;

⇒ 85 mL + 6 mL = 91 mL

The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL

5 0
3 years ago
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