Question

1f 3.8 kcal is released by combustion of each gram of

Answer 1

Answer:

1026.88 kilocalories are released by the combustion of 1.50 mol of glucose

Explanation:

First we have to calculate the amount in grams in 1.5 moles of glucose by using formula

Molecular mass of glucose is 180.156 g/mol

Mass in grams = Molarity x Molecular mass  

                       =1.50 moles x 180.156 g/mol

                       = 270.23 g

Now we will calculate the amount of energy released  

Energy released by 1 gram of glucose = 3.8 Kcal

Energy released by 270.23 gram of glucose = 3.8 x 270.23 Kcal

                                                                   = 1026.88 Kcal

1026.88 kilocalories are released by the combustion of 1.50 mol of glucose