a) The motion along the vertical direction and the motion along the horizontal direction.
b) The object remains in the air for a time period of 2usin(θ)/g.
Any object that is thrown in the air when gravity is acting on it is called a projectile. The motion of this projectile is called projectile motion.
When the projectile is thrown in the air at some angle θ, then there are two independent motions taking place at the same time. First is the component of motion along the vertical direction along which gravity acts. Second is the component of motion along the horizontal direction along which the object moves with a constant velocity. No force acts along the horizontal direction. The horizontal motion does not affect the vertical motion and the converse is also true. So these are independent of each other.
The time of flight is the time during which a projectile remains in the air. This time of flight is calculated using the formula,
T=2usin(θ)/g
where T is the time of flight, u is the initial velocity and g is the acceleration due to gravity.
Hence, the object remains in the air for a time period of 2usin(θ)/g.
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Answer:
<h2><u>Given </u><u>:</u><u>-</u></h2>
Mass = 25 kg
Height = 5 m
Acceleration due to gravity = 10 m/s
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>
Work done
<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>
We know that
W = mgh
W = 25 × 5 × 10
W = 250 × 5
W = 1250 J
Let applied force against the wall is F
now the Normal force on the block is given by
now friction force on the block will be given as
now net downwards force on the block will be
now this net downward force must be counterbalanced by upwards applied force
<em>so it required 109.1 N force to move it upwards</em>
Answer:
Explanation:
Given
Mass of car
Force applied
time period
Acceleration associated with car
Acceleration is the change in velocity w.r.t time
thus, the change in velocity is
20.9m = 1s
286.33m = 13.7s
To answer this you would multiply both sides by the amount of seconds she ran. The answer however is that she ran as far as 286.33m.