Answer: A) 45.5N b) 34.6N
Explanation:
Given the following :
Mass of block A(m1) = 5kg
Mass of block B (m2) = 6kg
Angle of incline (Θ) = 45°
Force pulling the down the incline = m1×a×sinΘ
Tension (T) = (m2×a) - (m2)×g
Where g = acceleration due to gravity
a = acceleration
Net force = (5×9.8×sin45°) - (6×9.8)
Net force = 34.648232 - 58.8
The net force acting on the body = 24.4N
Therefore,
Acceleration, a = Net force/ total mass
a = 24.4 / (6+5)
a = 2.22ms^-2
T = (m2 ×g) - (m2×a)
T = (6 × 9.8) - (6 × 2.22)
T = 58.8 - 13.32
T = 45.48
T = 45.5N
B) Normal reaction:
Horizontal component:
m1gCosΘ = 5 × 9.8 × cos45°
= 5 × 9.8 × 0.7071067
= 34.648232
= 34.6N
