The all purpose one will work or you could use type C I believe.
Solution :
Given :
k = 0.5 per day


Volume, V 
Now, input rate = output rate + KCV ------------- (1)
Input rate 


The output rate 
= ( 40 + 0.5 ) x C x 1000

Decay rate = KCV
∴
= 1.16 C mg/s
Substituting all values in (1)

C = 4.93 mg/L
Answer:
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Explanation:
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Answer:
correct me if i'm wrong but i think it's false
Explanation: