2 K3PO4 + 3 BaCl2 = 6 KCl + Ba3(PO4)2
reaction type: double replacement
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
reaction type: double replacement
2 HCl + K2CO3 = 2 KCl + H2O + CO2
i think there are two reactions here, so double replacement and decomposition
2 AgNO3 + Na2CO3 = Ag2CO3 + 2 NaNO3
reaction type: double replacement
2 Al2O3 = 4 Al + 3 O2
reaction type: decomposition
Answer:
Ethanoic or acetic acid.
Explanation:
Hello!
In this case, since the chemical formula of the compound excludes the hydrogen from the CHO form, we can infer it is a leaving group, which is likely to be bonded with an oxygen due to the high polarity of the O-H bond. In such a way, the most feasible condensed structure is:
Whereas the COOH stands for the carboxyl group; therefore the compound is ethanoic acid or acetic acid.
Regards!
Answer:
В. No, because the mass of the reactants is less than the mass of the products.
Explanation:
Chemical equation:
NaBr + Cl₂ → 2NaCl + Br₂
The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.
There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.
Balanced chemical equation:
2NaBr + Cl₂ → 2NaCl + Br₂
Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.
Answer:
Explanation:
For amount of radiation from a hot body there is Stefan's Boltzman's law which is given below .
E = e σ T⁴
E is amount emitted , e is emissivity , σ is stefan's constant = 5.67 X 10⁻⁸ W / m² . for earth e =.85 approx
E = .85 x 5.67 X 10⁻⁸ x T⁴
604 = .85 x 5.67 X 10⁻⁸ x T⁴
604 = 4.82 x 10⁻⁸ T⁴
T⁴ = 125.31 x 10⁸
T = 3.3457 x 10²
= 334.57K
Temperature in Celsius = 334.57 - 273
= 61.57 Celsius .
Answer:
The correct answer is option 3.
Explanation:
2A → B + C
First trial ;
[A] = x , Rate of the reaction = R
Rate law of the reaction can be written as:
..[1]
Second trial ;
[A] = 3x , Rate of the reaction = R' = 9R
Rate law of the reaction can be written as:
..[2]
[1] ÷ [2]
a = 2
Rate of the reaction :
The order of the reaction is 2. This is because in the rate law expression the the power of the concentration of reactant A id 2.