The gravitational force between the spheres is
where <em>G</em> = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
where <em>g</em> = 9.80 m/s².
The ratio between the two forces is then
A wagon is pulled by a handle making an upward angle of 25 degrees with a force of 25N. What is the horizontal force pulling the
wagon forward?
1 answer:
You might be interested in
Answer:
Part A:
Part B:
Explanation:
Part A:
Formula of Electric Field Strength:
Where:
x is the distance from the ring
R is the radius of the ring
is constant permittivity of free space=8.854*10^-12 farads/meter
Q is the charge
For right Ring E at the midpoint can be calculated as:
x for right plate=25/2=12.5 cm=0.125 m
Radius=R=10/2=5 cm=0.05 m
For Left Ring E at the midpoint can be calculated as:
Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.
Electric Field at midpoint:
Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.
Part B:
At center of left ring:
Due to left ring Electric field at center is zero because x=0.
Due to right ring Electric field at center of left ring:
Now: x=25 cm= o.25 m (To the center of left ring)
Electric Field Strength at center of left ring is same as that of right ring.