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iVinArrow [24]
3 years ago
13

A fluid with a relative density of 0.9 flows in a pipe which is 12 m long and lies at an angle of 60° to the horizontal At the t

op, the pipe has a diameter of 30 mm and a pressure gauge indicates a pressure of 860 kPa. At the bottom the diameter is 85 mm and a pressure gauge reading is 1 MPa. Assume the losses are negligible and determine the flov rate. Does the flow direction matter?
Engineering
1 answer:
Minchanka [31]3 years ago
4 0

Answer:

Q=7.3\times 10^{-3} m^3/s

Explanation:

Given that

At topd_2=30 mm,P_2=860 KPa ,P_1=1000 KPa,d_1=85 mm

\rho =900\dfrac{Kg}{m^3}

We know that

\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2

A_1V_1=A_2V_2

\frac{V_1}{V_2}=\left(\dfrac{d_2}{d_1}\right)^2

\frac{V_1}{V_2}=\left(\dfrac{30}{85}\right)^2

V_2=8.02V_1

Z_2=12 sin60^{\circ}

\dfrac{1000\times 1000}{900\times 9.81}+\dfrac{V_1^2}{2\times 9.81}+0=\dfrac{860\times 1000}{900\times 9.81 }+\dfrac{V_2^2}{2\times 9.81}+12 sin60^{\circ}

So V_1=1.30m/s

We know that flow rate Q=AV

Q=A_1V_1

By putting the values

A_1=\dfrac{\pi}{4}d^2

Q=7.3\times 10^{-3} m^3/s

To find the flow rate we do not need the direction of flow,because we are just doing balancing of energy at inlet and at the exits of pipe.

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Given that

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I.E.C. 180L motor frame

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