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Firdavs [7]
3 years ago
5

A balloon inflated at 25oC has a volume of 3.4 L. The balloon expands to 3.7 L. Assuming constant pressure, what is the new temp

erature?
Chemistry
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

T2=324.29k

Explanation:

V1=3.4L T1=25+273=298k

V2=3.7L T2=?

V1 V2

---- = ----

T1 T2

T2= V2×T1/V1

T2=(3.7×298)/3.4

T2=324.29k

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A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

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specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

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Putting the values in the equation:

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Now heat lost by metal = heat gained by water

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