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Firdavs [7]
3 years ago
5

A balloon inflated at 25oC has a volume of 3.4 L. The balloon expands to 3.7 L. Assuming constant pressure, what is the new temp

erature?
Chemistry
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

T2=324.29k

Explanation:

V1=3.4L T1=25+273=298k

V2=3.7L T2=?

V1 V2

---- = ----

T1 T2

T2= V2×T1/V1

T2=(3.7×298)/3.4

T2=324.29k

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The best option is melting point 
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During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound
sashaice [31]
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
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n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
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A change in the water temp of the Pacific Ocean that produces a warm current
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<h3><u>Answer;</u></h3>

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Answer:

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