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Readme [11.4K]
2 years ago
8

A visible violet light emits light with a wavelength of 4.00 × 10-7 m.

Physics
2 answers:
RideAnS [48]2 years ago
4 0

Answer:

The correct option is B. 7.5 * 10¹⁴ Hz

Explanation:

Frequency = (speed) / (wavelength)

= (3 x 10⁸ m/s) / (4 x 10⁻⁷ m)

= (3/4 x 10¹⁵) ( m / m - s )

= (0.75 x 10¹⁵) /sec

= 7.5 x 10¹⁴ Hz

= 750,000 GHz

ludmilkaskok [199]2 years ago
3 0

Answer:

Mark Brainliest please

answer is

Explanation:

For any wave,              

                          Frequency = (speed) / (wavelength)

                                             = (3 x 10⁸ m/s) / (4 x 10⁻⁷ m)

                                             = (3/4 x 10¹⁵)  ( m / m - s )

                                             = (0.75 x 10¹⁵)  /sec

                                             =  7.5 x 10¹⁴  Hz

                                             =   750,000 GH

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Answer:

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Explanation:

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Alcohol of mass 33.2g and density 0.79kg/m³ or 790kg/m³ is mixed with water of 9g. What is the density of the resulting mixture?
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Answer:

  0.83 g/cm³

Explanation:

The volume of the alcohol is ...

  (33.2 g)/(0.79 g/cm³) ≈ 42.0253 cm³

The density of water is about 1 g/cm³, so the volume of 9 g of it is ...

  (9 g)/(1 g/cm³) = 9 cm³

The total volume is ...

  42.0253 cm³ +9 cm³ = 51.0253 cm³

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So, the resulting density is ...

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The resulting mixture has a density of about 0.83 g/cm³.

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<em>Additional comment</em>

Alcohol dissolves in water, so the total volume will be slightly less than 51.0253 cm³. The attached curve shows the result of mixing ethanol and water.

The weight of a mole of ethanol is about 46 g, of water, about 18.02 g. Then the mole fraction of alcohol is ...

  (33.2/46)/(33.2/46 +9/18.02) ≈ 0.59

The volume of the mix is then estimated to be (-1.05 cc/mol)(1.221 mol), or about 1.28 cm³ less than the volume indicated above. That brings the density up to about 0.85 g/cm³.

We're not completely sure of the relevance of this calculation, since many of the applicable parameters are not specified. The point is that <em>the density of the mix will probably be slightly more than the value calculated above</em>. YMMV

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