If light travels 300,000 km/s how long does light reflected from mars take to reach earth when mars is 65,000,000 km away

"the total angular momentum of an object changes when a net external force acts on the system." This statement is:

labwork [276]

Here is the answer of the given question above. "The total angular momentum of an object changes when a net external force acts on the system." This statement is <span>"sometimes true. it depends on the forces point of application". The answer is option D.
</span>

6 0

3 years ago

If there is an unusually windy month one might anticipate a. Higher tides b.increased wave size c. Unpredictable currents d. Low

Luden [163]

I belive it is b. increased wave size

6 0

3 years ago

Rubbing your hands together warms them by converting work into thermal energy. If a woman rubs her hands back and forth for a to

Feliz [49]

Answer:

Explanation:

Total heat = Work done = Force × distance

distance = 0.075 × 12 = 0.9 m

W = 45 × 0.9 = 40.5 joules

Specific heat of the human hand = 3.5 kj/kg = 3.5 j/g

Q = MCΔT

ΔT = (Q) ÷ (MC)

ΔT = 40.5 ÷ (3.5 × 1) = 11.57°C

5 0

2 years ago

A stone tied at one end of the string is whirled in vertical circle, where is the tension in the string be maximum and minimum?

Ber [7]

<h3>answer</h3>

The minimum velocity required for a object to rotate in a verticle plane is v

1

=

5

gr.

So, at bottom point, T

max

=mv

1

2

/r+mg=6mg.

At top-most point velocity is v

2

=gr.

So, T

min

=mv

2

/r−mg=0

So T

max

−T

min

=6mg=2×g⇒m=1/3 kg

4 0

2 years ago

Three point charges are arranged on a line. Charge q3 = 5 nC and is at the origin. Charge q2 = - 3 nC and is at x = 4 cm. Charge

Taya2010 [7]

Answer:

q₁ = + 1.25 nC

Explanation:

Theory of electrical forces

Because the particle q₃ is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.

Known data

q₃=5 nC

q₂=- 3 nC

d₁₃= 2 cm

d₂₃ = 4 cm

Graphic attached

The directions of the individual forces exerted by q1 and q₂ on q₃ are shown in the attached figure.

For the net force on q3 to be zero F₁₃ and F₂₃ must have the same magnitude and opposite direction, So, the charge q₁ must be positive(q₁+).

The force (F₁₃) of q₁ on q₃ is repulsive because the charges have equal signs ,then. F₁₃ is directed to the left (-x).

The force (F₂₃) of q₂ on q₃ is attractive because the charges have opposite signs. F₂₃ is directed to the right (+x)

Calculation of q1

F₁₃ = F₂₃