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AlexFokin [52]
3 years ago
10

If light travels 300,000 km/s how long does light reflected from mars take to reach earth when mars is 65,000,000 km away

Physics
1 answer:
azamat3 years ago
6 0
About <span>216.6 seconds if my math is correct.</span>
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adoni [48]

Answer:

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Explanation:

5 0
2 years ago
Explain why a diverging lens is used to correct nearsightedness (difficulty seeing objects far away).
Darina [25.2K]

Answer:

so that it can diverge the light to make sure that it focused on the ratina and the image is formed.

Explanation:

nearsightedness is when the light is focused in front of the ratina and for an image to be formed in the eye, the light must be focused on the ratina so to correct that we use the diverging lenses so that it will diverge the light and allow the cornea and the lens to converge it so it is focused on the ratina.

8 0
3 years ago
Read 2 more answers
Solve this question
Rudik [331]
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6 0
2 years ago
A rifle that shoots bullets at 477 m/s is to be aimed at a target 45.5 m away. If the center of the target is level with the rif
Free_Kalibri [48]

Answer:

The rifle barrel must be pointed at a height of 4.45cm above the target so that the bullet hits dead center.

Explanation:

First, we need to sketch the situation so we can have a better idea of what the problem looks like (Refer to uploaded picture).

So as you may see in the drawing, when pointing the rifle to the target, we can see it as a triangle, but in reality, the bullet will have a parabolic trajectory. Both points of view will help us determine what the height must be. In order to find it, we need to first determine at what angle the bullet should be shot. In order to do so we can use the range formula, which looks like this:

R=\frac{v^{2}sin(2\theta)}{g}

Where R is the range of the bullet (this is how far it goes before it has the

same height it was shot from), v is the original speed of the bullet, θ is the angle at which the bullet is shot and g is the acceleration of gravity.

We can solve this equation for theta, so we get:

gR=v^{2}sin(2\theta)

\frac{gR}{v^{2}}=sin(2\theta)

sin^{-1}(\frac{gR}{v^{2}})=2\theta

\theta=\frac{sin^{-1}(\frac{gR}{v^{2}})}{2}

so now we can substitute the given data:

\theta=\frac{sin^{-1}(\frac{(9.8m/s^{2})(45.5m)}{(477m/s)^{2}})}{2}

so we get:

θ=0.05614°

once we get the angle, we can look at the triangle diagram. From the drawing we can see that we can use the tan function to find the height:

tan \theta = \frac{h}{45.5m}

so we can solve this for h, so we get:

h=45.5m*tan(0.05614^{o})

which yields:

h=0.0445m

or

h=4.45cm

5 0
2 years ago
What is kinetic energy? Question 1 options: energy that is due to motion energy that is stored the mass of an object the rate at
mario62 [17]
<span>Kinetic Energy means energy that a body possesses by virtue of being in motion. I hope this helps!!!</span>
8 0
3 years ago
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