Option (c) is correct.
Explanation:
initial velocity along vertical=0
velocity along horizontal Vx=40.20 m/s
acceleration along the vertical=9.8 m/s²
displacement along vertical,h=2 m
using the kinematic equation
h= vi*t + 1/2 g t²
2=0(t) + 1/2 (9.8)t²
t²=0.408
t=0.639 s
now the displacement along vertical= x= Vx* t
x=40.20 (0.639)
x=25.73 m
Answer:
14.49 N
Explanation:
East component (x component)
=15 m * cos 15°
=14.49N
Answer:
Choices A, B, and C are correct.
Explanation:
Let us look at each of the choices one by one:
A. It is a vector
Yes. Velocity is a vector, or it's a speed with direction.
B. It is the change in displacement divided by the change in time.
Yes. The velocity can be written as

where
is the displacement—a vector quantity.
C. It can be measured in meters per second.
Yes. The units of velocity are m/s, but also with a unit vector indicating the direction.
D. It is the slope of the acceleration vs. time graph.
Nope. The velocity is the slope of displacement vs. time graph.
Hence, only choices A, B, and C are correct.
Answer:
Explanation:
W = 75 watts
V = 110 volts
Formula
W = V * I
Solution
75 = 110 * I Divide by 110
75 / 110 = I
I = 0.6818 Amperes
The tension in the cable is 169.43 N and the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
<h3>Tension in the cable</h3>
Apply the principle of moment and calculate the tension in the cable;
Clockwise torque = TL sinθ
Anticlockwise torque = ¹/₂WL
TL sinθ = ¹/₂WL
T sinθ = ¹/₂W
T = (W)/(2 sinθ)
T = (29 x 9.8)/(2 x sin57)
T = 169.43 N
<h3>Vertical component of the force</h3>
T + F = W
F = W - T
F = (9.8 x 29) - 169.43
F = 114.77 N
Thus, the tension in the cable is 169.43 N and the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
Learn more about tension here: brainly.com/question/24994188
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