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nydimaria [60]
2 years ago
10

PLZ HELP DUE TODAY ! ! ! ! A student built the following circuit from a diagram. What can the student do to make this a complete

scientific investigation?
The student can complete the same experiment outside.

The student can try completing the experiment in the dark.

The student can use completely new materials and do a different experiment.

The student can change the size of the battery and see what happens.

Physics
2 answers:
Kamila [148]2 years ago
8 0
I would say the last one but I’m not sure if I’m directly correct ..
Anettt [7]2 years ago
6 0
The correct answer is a (: enjoy!
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3 years ago
Based on the information presented in the graph, what is the velocity of the object?
Sladkaya [172]

Answer:

3 m/s

Explanation:

<u>The velocity of a position-time graph is the slope of the line.</u>  Slope is rise over run, or rise divided by run.  The rise (how many units the line goes up) is 3 units and the run is 1 unit.  3/1 is 3, so the velocity is 3 m/s.

7 0
3 years ago
If a car goes at a speed of 80 kph in 10 seconds, what is the distance
Blababa [14]

Answer:222 meters

Explanation:

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3 0
3 years ago
A point charge with charge q1 = 4.00 μC is held stationary at the origin. A second point charge with charge q2 = -4.40 μC moves
Bezzdna [24]

Answer:

W=0.94J

Explanation:

Electrostatic potential energy is the energy that results from the position of a charge in an electric field. Therefore, the work done to move a charge from point 1 to point 2 will be the change in electrostatic potential energy between point 1 and point 2.

This energy is given by:

U=\frac{K\left |q_1 \right |\left |q_2 \right |}{r}\\

So, the work done to move the chargue is:

W=U_1-U_2\\W=\frac{K\left |q_1 \right |\left |q_2 \right |}{r_1}-\frac{K\left |q_1 \right |\left |q_2 \right |}{r_2}\\r_1=\sqrt{((0.155 m)^2+0 m)^2}=0.115m\\r_2=\sqrt{((0.245 m)^2+(0.270 m)^2}=0.365m\\W=K\left |q_1 \right |\left |q_2 \right |(\frac{1}{r_1}-\frac{1}{r_2})\\W=8.99*10^9\frac{Nm^2}{c^2}(4.00*10^{-6}C)(4.40*10^{-6}C)(\frac{1}{0.115m}-\frac{1}{0.365})\\W=0.94J

The work is positive since the potential energy in 1 is greater than 2.

5 0
3 years ago
Use your knowledge of waves and the graph shown to determine the frequency of wave C. What does it tell you about speed of the w
stealth61 [152]

Answer

10

Explanation:

goes up by 10 each time 10 to 20 to 30

6 0
2 years ago
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