All categories

3 years ago

Farmer Tamar airlifted her sheep from 1000 meters to 1,200 meters

Physics

1 answer:

attashe74 [19]3 years ago

4 0

Question

What was the change in potential energy of the sheep?

Answer:

1962(m) J

Explanation:

Potential energy is given by

PE=mgh

Change in potential energy is given by

∆PE=mg(h2-h1)

Where ∆PE is the change in potential eneegy, g is acceleration due to gravity, h2 is final height and h1 is the initial height.

Substituting 9.81 m/s² for g, 1200 m for h2 and 1000 m for h1 then

∆PE=m*9.81(1200-1000)=1962m Joules

Since we are not given the mass of rhe sheep, the answer will be 1962(m) Joules

You might be interested in

According to the ideal gas law, a 1.074 mol sample of oxygen gas in a 1.746 L container at 267.6 K should exert a pressure of 13

luda_lava [24]

Answer:

% differ 1.72%

Explanation:

given data:

P_ideal = 13.51 atm

n = 1.074 mol

V = 1.746 L

T = 267.6 K

According to ideal gas law we have

$(P+ \frac{n^2 *a}{v^2}) (V - nb) = nRT$

$(P+ (\frac{1.074^2 *1.360}{1.746^2})) (1.746 - 1.074*3.183*10^{-2}) = 1.074*0.0821*267.6$

(P+0.514)(1.711) = 23.59

P_v = 13.276 atm

% differ $= \frac{ P_I - P_v}{P_I} *100$

$= \frac{13.51 - 13.27}{13.51} *100$

= 1.72%

3 0

4 years ago

Which statement best compares an asteroid with Earth?

IgorLugansk [536]

Answer:C) Both have rocky composition

6 0

3 years ago

The unit of power of a lens is.<br>(a) Metre<br>(b) Dyne<br>(c) Dioptre

zhenek [66]

Answer:

c. dioptre that's the answer.

5 0

3 years ago

Read 2 more answers

Two identical satellites are in orbit about the earth. One orbit has a radius r and the other 2r. The centripetal force on the s

velikii [3]

Answer:

the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

Explanation:

Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2 = 2r

Centripetal force is given by

$F= \frac{mv^{2}}{r}$

Where v be the orbital velocity, which is given by

$v=\sqrt{gr}$

So, the centripetal force is given by

$F= \frac{mgr}}{r}}=mg$

where, g bet the acceleration due to gravity

$g=\frac{GM}{r^{2}}$

So, the centripetal force

$F= \frac{GMm}}{r^{2}}}$

Gravitational force on the satellite having larger orbit

$F= \frac{GMm}{4r^{2}}$ .... (1)

Gravitational force on the satellite having smaller orbit

$F'= \frac{GMm}{r^{2}}$ .... (2)

Comparing (1) and (2),

F' = 4 F

So, the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

8 0

4 years ago

ELECTROMAGNETIC FIELDS PLAN AN INVESTIGATION LAB REPORT FOR EDG.!!!!! WORTH 100 POINTS????????

tekilochka [14]

Answer:ummm ok

Explanation:I really don’t get it but ok

3 0

3 years ago