Question

A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located at the center of the sphere and point B is 15 cm from the center, what is the magnitude of the electric potential difference between these two points?

Answer 1

Answer:

$\Delta V = 30V$

Explanation:

give data:

inside diameter = 5.0 cm

charge q = 0.25 nC

Outside diameter = 15 cm

potential V at inside sphere is = $V=\frac{kq}{R}$

potential V at outside sphere is = $V=\frac{kq}{r}$

k is constant whose value is = $8.99 *10^{9}Nm^{2}/c^2$

then potential difference between two point is

$\Delta V = kq \left [\frac{1}{R}-\frac{1}{r} \right ]$

$\Delta V = 9*10^{9}*0.25*10^{-9} \left [\frac{1}{0.05}-\frac{1}{0.15} \right ]$

$\Delta V = 30V$