Question

Bragg's law for x-ray diffraction is 2d sin8-mk, where ? is the angle between the incident beam and: the refracted beam e a reflecting plane of atoms the normal to the scattered beam the scattered beam the normal to a reflecting plane of atoms

Answer 1

Explanation:

Bragg's law is given by :

$2d\ sin\theta=n\lambda$

Where

d is the lattice spacing

n is the order

$\lambda$ is the wavelength of x- ray

$\theta$ is the diffraction angle.

Diffraction angle is defined as the angle between incident beam and the reflecting planes of atom. Hence, the correct option is (b).