Answer:
Therefore, the value of K_{p} is 2 \times 10^{9} and value of \Delta G^{o} is -53.2 kJ/mol.
Explanation:
Answer:
15.5 moles
Explanation:
Applying,
PV = nRT.................. Equation 1
Where P = pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
Make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.
Constant: R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.899×425)/(297×0.083)
n = 15.5 moles
If the student forgot to calculate 12 H2O molecule from the compound, that means the compound molecular mass used will be much lower than it should. If the molecular mass calculated lower than it should, then the percent yield would be increased.
If the student fixes the compound mass, then the yield will become lower than the first result.
You must always wear goggles.
