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Kisachek [45]
4 years ago
7

A steel railroad track has a length of 31 m

Physics
1 answer:
Bess [88]4 years ago
7 0

Answer:

DL = 0.0105 [m] = 10.57 [mm]

Explanation:

To solve this problem, we use the following equation that involves length changes depending on temperature changes.

DL=\alpha *DT*L

where:

DL = length change

α = thermal expansion coefficient = 11 * 10^(-6) [1/°C]

DT = temperature change = (37-6) = 31 [°C]

L = nominal or initial  length = 31 [m]

DL = 11 * 10^(-6) * 31 * 31

DL = 0.0105 [m] = 10.57 [mm]

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The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which
Slav-nsk [51]

Answer:

V = 5.24m/s

Explanation:

See attachment below.

5 0
4 years ago
A sealed cubical container 10.0 cm on a side contains three times Avogadro's number of molecules at a temperature of 24.0°C. Fin
rodikova [14]

This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

PV = nRT

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)

R = general gas constant = 8.314 J/mol.K

T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

P = \frac{(3)(8.314\ J/mol.k)(297\ K)}{0.001\ m^3}

P = 7407.78 KPa

Now, the force on one wall can be given as follows:

P =\frac{F}{A}\\\\F=PA

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

F=(7407.78\ KPa)(0.01\ m^2)\\

<u>F = 74.08 KN</u>

<u></u>

Learn more about the general gas equation here:

brainly.com/question/24645007?referrer=searchResults

5 0
3 years ago
Four spheres with positive and negative charges hang from strings.
Arada [10]
Be because it’s the answer
5 0
3 years ago
What is the repulsive force between two pith balls that are 10.0 cm apart and have equal charges of -40.0 NC?
galina1969 [7]

Answer:

So the repulsive force between the pith ball will be 1.44\times 10^{-3}N

Explanation:

We have given that the pith ball have the equal charge q = -40 nC =-40\times 10^{-9}C

Distance between the charges = 10 cm =0.1 m

According to coulombs law F=\frac{KQ_1Q_2}{R*2}

F=\frac{9\times 10^9\times -40\times 10^{-9}\times -40\times 10^{-9}}{0.1^2}=1440000\times 10^{-9}=1.44\times 10^{-3}N

So the repulsive force between the pith ball will be 1.44\times 10^{-3}N

5 0
3 years ago
What is the relationship between the strength of an
Anastaziya [24]

Answer:

As the number of turns in the coil increases, the strength  of the electromagnet increases.

Explanation:

When current flows through a coil the coil behaves as an electromagnet. The strength of electromagnet depend the amount of current, no of turns of coil and the core of coil.

B=μ₀ N I

μ₀ = permeability of the core

N = Number of turns of the coil

I = Current flowing through the coil

Increasing the current and number of coils increase the strength of electromagnet.

3 0
4 years ago
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