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Nezavi [6.7K]
3 years ago
13

Under what conditions will the front of a glacier remain stationary?

Physics
1 answer:
goblinko [34]3 years ago
5 0
<span>When melting and snow accumulation are equal.</span>
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Using complete sentences and your own words describe some of the ways humans use water.
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Answer:

Humans use water for many different things. We use water to stay hydrated. Our bodies need water to live. Back in the day people used water for transportation and trading. This was a way to become wealthy and exchange goods and ideas from one place to another. We also use water to clean ourselves off. If we don't we can become sick with illnesses that can harm our bodies.

Explanation:

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what is the source of centripetal force that planet requires revolving around the sun on what basis the factor does that was the
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Sixty-three joules of heat are added to a closed system. The initial internal energy of the system is 58 J, and the final intern
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Global expansion offers companies the opportunity to generate greater profits than companies that focus strictly on _____.
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Answer:

The domestic market

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Global expansion does, in fact offer companies the opportunity to generate greater profits than companies that focus strictly on the domestic market.

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6 0
3 years ago
Copper and aluminum are being considered for a high-voltage transmission line that must carry a current of 51.5 A. The resistanc
Sliva [168]

Answer:

a).Jcu= 436.44x10^{3} \frac{A}{m^{2}}

b).λcu=1.05728 \frac{kg}{m}

c).Jal= 274.66 x10^{3} \frac{A}{m^{2}}

d).λcu=0.487 \frac{kg}{m}

Explanation:

a).

ζcu=1.7x10^{-8}Ωm

ζal=2.76x10^{-8}Ωm

A=\frac{w}{R}

wcu=ζcu*l

Acu=\frac{1.7x10^{-8}*1000}{0.144} =1.18x10^{-4} m^{2}

J=\frac{I}{Acu}=\frac{51.5A}{1.18x10^{-4}m^{2}} \\J=436.44x10^{3} \frac{A}{m^{2}}

b).

mass per unit Copper

λcu=Dcu*Acu

λcu=8960 \frac{kg}{m^{3}}*1.18x10^{-4} m^{2}

λcu=1.05728 \frac{kg}{m}

c).

wal=ζal*l

Aal=\frac{2.7x10^{-8}*1000}{0.144} =0.187x10^{-3} m^{2}

J=\frac{I}{Aal}=\frac{51.5A}{0.187x10^{-3}m^{2}} \\J=274.66x10^{3} \frac{A}{m^{2}}

d).

mass per unit Aluminum

λal=Dal*Aal

λal=2600 \frac{kg}{m^{3}}*0.1875x10^{-3} m^{2}

λcu=0.487 \frac{kg}{m}

3 0
3 years ago
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