Answer:
hufiui
fihgpfghlfikgergkfkjhfkhjgkffhhh
Explanation:
jjgzgcjxhgygueyuufhfugkhkckgijljhgxjgjgffhgkgjxhxjgjcjckvjgghkhkgjgjfhfhfhffrusufsflslrsyfhldufñlñudtoqdyhjjxkgsgjfktwlyfñujxjxhlxlhdktstedoyñfuyñflldytidoyeyljjcñcjluffñui5woyepurñfuñufldyrajuñdlydstdyñudñydktshñxjcñydiw5uñfitwoyeoyeñufñfuñifjñufhlsyñeifññydoysitaiwtuñdyñdlsyltslsyoyeylsuñdñjjcyldlyslatlysñudidñjdñfjñjjxlhsmzhmzjjdjdlhdñhjdñjdñjddñhflhuñfhxltkds4urayraylraluarularuñstuñtsuñtsultsuñtsuñstñitsñktssistustlulsrustlularyralultalutslutajltsñgskjlgzljg?g o uguhxputxipyfugxiñhxiñhfuñdguldthgksjmgdjmgkhdjlgdjlgd
pduoyditsyafylrayoraourauptautospustistiptsñitsñitsñitsiptsiteitdustuñtsuñtsñitwiñstñitwñitsñstuuñrsoursurosoustjlsrlutejlgsjlstjfsjlgsultsjgzjñgsññkdylfhkñdgjlfshkadmjgsuñstñkydñkydñiykdhiñstñitsuñtsisñtñtieñietñietñiteñiwtñitskñgsiñteuñwrkñsturaluglsuñtwjlfalfjalhadoyfutdllgdñitswtkgsñktjrajtsurwñwñutiñtsiwñtuwñturqlñitwualtayoryarluarlietite
Answer:
E- The star becomes a red giant (LATEST STAGE)
F- The surface of the star becomes brighter and cooler
C- Pressure from the star's hydrogen-burning shell causes the non burning envelope to expand
A- The shell of hydrogen surrounding the star's nonburning helium core ignites.
D- The star's non burning helium core starts to contract and heat up
B- Pressure in the star's core decreases (EARLIEST STAGE)
(A star moves away from the main sequence once its core runs out of hydrogen to fuse into helium. The energy once supplied by hydrogen burning reduces and the core starts to compress under the force of gravity. This contraction allows the core and surrounding layers to heat up. Finally, the hydrogen shell around the core becomes hot enough to ignite hydrogen burning.
Valleys are one of the most common landforms on the Earth and they are formed through erosion or the gradual wearing down of the land by wind and water. In river valleys for example, the river acts as an erosional agent by grinding down the rock or soil and creating a valley
Answer:
Explanation:
After the collision velocity of the particle is (4î - 3ĵ)m/s . ... A particle of mass 1 kg moving with a velocity of (4i^−3j^)m/s collides with a fixed surface. ... Perfectly inelastic. D ... The common velocity of the blocks after collision is: ... A ball falls from a height of 5 m and strikes the roof of a lift. ... Stay upto date with our Newsletter! i know this is not right but just here for points see ya loser
1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.
<u>Explanation</u>:
We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the
and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:

Better understood from numerical example as given:
If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?
This can be solved as follows:


It shows that man A will have more K.E.
Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.