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andriy [413]
3 years ago
12

In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu

estion about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.
Physics
3 answers:
Rama09 [41]3 years ago
7 0

Answer:

We shall consider two properties:

1. Temperature difference

2. Thermal conductivity of the material

Use a cylindrical rod of a given material (say steel) which is insulated around its circumference.

One end of the rod is dipped in a large reservoir of water at 100 deg.C and the other end is dipped in water (with known volume) at 40 deg. C. The cold water if stored in a cylinder which is insulated on all sides. A thermometer reads the temperature of the cold water as a function of time.

This experiment will show that

(a) heat flows from a region of high temperature to a region of lower temperature.

(b) The thermal energy of a body increases when heat is added to it, and its temperature will rise.

(c) The thermal conductivity of water determines how quickly its temperature will rise. If mercury replaces water in the cold cylinder, its temperature will rise at a different rate because its thermal conductivity is different.

Explanation:

USPshnik [31]3 years ago
5 0

Answer:

the effect would be 2w=btyh,3

Explanation:

Jayy3 years ago
0 0

answer: How do mass and the type of material affect thermal energy transfer
on edg its right

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Yes. Everybody on Earth sees the same moon phase at the same time.
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3 years ago
As a result of air at the top of a barometer the height of the mercury column is 73.5cm when it should be 75.0 cm the volume of
MakcuM [25]

Explanation:

Using p1p1=p2p2

(75-73.5)x8=(X - 74)X 6

1.5 X 8= 6x-444

12=6x-444 (add 12)

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5 0
3 years ago
A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia
aivan3 [116]

Answer:

\Delta V=V_{2}-V_{1}=45.4V

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

E=\frac{1}{2} CV^{2}

V=\sqrt{2E/C}

If we increase the Voltage, the Energy increase also:

V_{1}=\sqrt{2E_{1}/C}

V_{2}=\sqrt{2E_{2}/C}

The voltage difference:

V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}

V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V

5 0
3 years ago
Two students stand poised to leap off a high dive structure into the swimming pool below. Student B is twice as massive as stude
iogann1982 [59]

Answer: option (D)

Explanation:

The potential energy of each of the students is given below as

P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.

The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as

P.E ( student B) =2mgh = 2(mgh)

Recall that the relationship between potential energy and work done is that

Work done = - (change in potential)

For student A, work done = - mgh

For student B, work done = - 2mgh

From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.

8 0
3 years ago
How many significant figures does the number 0.0030 have?<br><br> A) 1<br> B) 2<br> C) 4<br> D) 3
aniked [119]
My Answer: b)2

Scientific Notation: 3.0 × 10^-3
8 0
3 years ago
Read 2 more answers
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