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andriy [413]
3 years ago
12

In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu

estion about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.
Physics
3 answers:
Rama09 [41]3 years ago
7 0

Answer:

We shall consider two properties:

1. Temperature difference

2. Thermal conductivity of the material

Use a cylindrical rod of a given material (say steel) which is insulated around its circumference.

One end of the rod is dipped in a large reservoir of water at 100 deg.C and the other end is dipped in water (with known volume) at 40 deg. C. The cold water if stored in a cylinder which is insulated on all sides. A thermometer reads the temperature of the cold water as a function of time.

This experiment will show that

(a) heat flows from a region of high temperature to a region of lower temperature.

(b) The thermal energy of a body increases when heat is added to it, and its temperature will rise.

(c) The thermal conductivity of water determines how quickly its temperature will rise. If mercury replaces water in the cold cylinder, its temperature will rise at a different rate because its thermal conductivity is different.

Explanation:

USPshnik [31]3 years ago
5 0

Answer:

the effect would be 2w=btyh,3

Explanation:

Jayy2 years ago
0 0

answer: How do mass and the type of material affect thermal energy transfer
on edg its right

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A charged object is suspended motionless in the air by the gravitational force pulling it down and an electric force pushing it
Savatey [412]

The charge of the object must be 1.11 \times e^{-5} \text { coulomb }

Answer: Option C

<u>Explanation:</u>

Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.

Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

         Electric field, E=\frac{\text { Force }(F)}{q}

Here, given E = 4500 N/C and F = 0.05 N.

We need to find charge of the object (q)

By substituting the given values, we get

      q=\frac{F}{E}=\frac{0.05 N}{4500 \mathrm{N} / \mathrm{c}}=1.11 \times e^{-5} \text { coulomb }

6 0
3 years ago
How did Koch choose candidates?​
Salsk061 [2.6K]
They choose the ones who talk the most and could be seen as leaders
4 0
2 years ago
Through what angle in degrees does a 33 rpm vinyl record turn in 0.23 s : A) 46° B) 26° C) 53° D) 33°
solniwko [45]

Answer:

(a) angle record will be 46°

Explanation:

We have given speed = 33 rpm

Time t = 0.23 sec

We know that 1 revolution = 360°

And 1 minute = 60 sec

So 33 revolution/minute \frac{33\times 360}{60}=198^{\circ}/sec

So angle record by vinyl =198\times 0.23=45.54^{\circ} , which is nearly equal to 46

So angle record by vinyl is 46°

So option (a) will be the correct answer

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What is someones target heart rate at 70% at age 17​
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Answer: normal

Explanation:

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2 years ago
How much energy, in joules, is released when 17 kilograms of granite is cooled from 45°C to 21°C?
zepelin [54]
The final answer is -322, 320 Joules. The solution for the problem is:

The equation that must be used in this problem is:

U = mCp(Tf-Ti)

where:
U = energy released or absorbed in Joules
m = mass in kg
Cp = specific heat of material in J/kg-C
Tf = final temperature, C
Ti = initial temperature, C

Looking up the Cp of granite gives a value of 790 J/kg-C.

U = 17kg (790 J/kg-C) (21-45)
<span>U = - 322, 320 Joules (negative means heat is released)</span>
4 0
3 years ago
Read 2 more answers
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