The charge of the object must be 
Answer: Option C
<u>Explanation:</u>
Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.
Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

Here, given E = 4500 N/C and F = 0.05 N.
We need to find charge of the object (q)
By substituting the given values, we get

They choose the ones who talk the most and could be seen as leaders
Answer:
(a) angle record will be 46°
Explanation:
We have given speed = 33 rpm
Time t = 0.23 sec
We know that 1 revolution = 360°
And 1 minute = 60 sec
So 33 revolution/minute 
So angle record by vinyl
, which is nearly equal to 46
So angle record by vinyl is 46°
So option (a) will be the correct answer
The final answer is -322, 320 Joules. The solution for the problem is:
The equation that must be used in this problem is:
U = mCp(Tf-Ti)
where:
U = energy released or absorbed in Joules
m = mass in kg
Cp = specific heat of material in J/kg-C
Tf = final temperature, C
Ti = initial temperature, C
Looking up the Cp of granite gives a value of 790 J/kg-C.
U = 17kg (790 J/kg-C) (21-45)
<span>U = - 322, 320 Joules (negative means heat is released)</span>