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RSB [31]
3 years ago
8

1. What are the characteristics of winds?

Physics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

wind has two important things that is direction and speed.

You might be interested in
he membrane that surrounds a certain type of living cell has a surface area of 6.0 x 10-9 m2 and a thickness of 1.6 x 10-8 m. As
k0ka [10]

Answer:

1.54481175\times 10^{-12}\ C

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

A = Area = 6\times 10^{-9}\ m^2

d = Thickness = 1.6\times 10^{-8}\ m

k = Dielectric constant = 5.4

V = Voltage = 86.2 mV

Charge is given by

Q=CV\\\Rightarrow Q=k\epsilon\dfrac{A}{d}V\\\Rightarrow Q=5.4\times 8.85\times 10^{-12}\times \dfrac{6\times 10^{-9}}{1.6\times 10^{-8}}\times 86.2\times 10^{-3}\\\Rightarrow Q=1.54481175\times 10^{-12}\ C

The charge on the outer surface is 1.54481175\times 10^{-12}\ C

4 0
3 years ago
Describe how wet and dry barometers work
siniylev [52]

Answer: Wet barometer - The tool works by measuring atmospheric pressure to predict incoming weather. Since the glass is only filled halfway with water, the other half is exposed to the atmosphere. When the outdoor atmospheric pressure rises, the pressure in the glass decreases, and causes the water to move down the spout.

Dry barometer - A Torricellian barometer (sometimes called a mercury barometer) is an inverted (upside-down) glass tube standing in a bath of mercury. Air pressure pushes down on the surface of the mercury, making some rise up the tube. The greater the air pressure, the higher the mercury rises.

I hope this helps!

7 0
3 years ago
Can someone explain how the weight of the block is 10.26N, with reference to an appropriate law of motion?
spayn [35]

this process is called parellelogram method of resolving vectors.

5 0
4 years ago
Dimension of specific heat capacity​
Luden [163]

Answer:

The specific heat of a substance (per unit of mass) has dimension L. T. Θ−1, or (L/T)2/Θ. Therefore, the SI unit J/K/kg is equivalent to metre squared per second squared per kelvin (m2 K−1 s−2).

3 0
3 years ago
A fighter jet is launched from an aircraft carrier with the aid of its own engines and a steam-powered catapult. The thrust of i
kirza4 [7]

Answer:

2.5 x 10⁷ J

Explanation:

F = thrust of the engine = 2.3 x 10⁵ N

d = distance traveled = 87  m

Work done by the engine is given as

W = F d =  (2.3 x 10⁵) (87) = 200.1 x 10⁵ J

W' = Net work done

W'' = work done by catapult

KE₀ = initial kinetic energy = 0 J

KE = final kinetic energy = 4.5 x 10⁷ J

Net work done is given as

W' = KE - KE₀

W' = 4.5 x 10⁷ J

We know that

W' = W + W''

4.5 x 10⁷ = 2.001 x 10⁷ + W''

W'' = 2.5 x 10⁷ J

8 0
3 years ago
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