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satela [25.4K]
3 years ago
6

Of the core elements of successful safety and health programs,management leadership,worker participation and what else directly

relate to individuals
roles
Engineering
1 answer:
ch4aika [34]3 years ago
7 0
I think it would definitely be dinvi and the ghosts just because I really relate to that story
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A well is located in a 20.1-m thick confined aquifer with a conductivity of 14.9 m/day and a storativity of 0.0051. If the well
ahrayia [7]

Answer:

S = 5.7209 M

Explanation:

Given data:

B = 20.1 m

conductivity ( K ) = 14.9 m/day

Storativity  ( s ) = 0.0051

1 gpm = 5.451 m^3/day

calculate the Transmissibility ( T ) = K * B

                                                       = 14.9 * 20.1 = 299.5  m^2/day

Note :

t = 1

U = ( r^2* S ) / (4*T*<em> t </em>)

  = ( 7^2 * 0.0051 ) / ( 4 * 299.5 * 1 ) = 2.0859 * 10^-4

Applying the thesis method

W(u) = -0.5772 - In(U)

       = 7.9

next we calculate the pumping rate from well ( Q ) in m^3/day

= 500 * 5.451 m^3 /day

= 2725.5 m^3 /day

Finally calculate the drawdown at a distance of 7.0 m form the well after 1 day of pumping

S = \frac{Q}{4\pi T} * W (u)

 where : Q = 2725.5

               T = 299.5

               W(u)  = 7.9

substitute the given values into equation above

S = 5.7209 M

4 0
3 years ago
What happens to the duty cycle for a GMAW Gun when 75Ar/25COzgas
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So what happens is the host will not kill the y no se que hacer para no one can see it in

6 0
2 years ago
A semiconductor is a solid substance that has a conductivity between that of an insulator and that of most metals. (True , False
tiny-mole [99]

The answer is : True

4 0
3 years ago
: Câu nào dưới đây thể hiện sự thiếu tự chủ?
sukhopar [10]

Answer:

thành thật mà nói bởi vì cách những chiếc lá đang chuyển và cách mặt trời chiếu sáng.

3 0
2 years ago
For a turbulent flow of a fluid in 0.6 m diameter pipe, the velocity 0.15 m from the wall is 2.7 m/s. Estimate the wall shear st
MAVERICK [17]

Answer:

If the turbulent velocity profile in a pipe of diameter 0.6 m may be approximated by u/U=(y/R)^(1/7), where u is in m/s and y is in m and 0.15 m from the pipe.

Explanation:

hope it helps

3 0
2 years ago
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