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GuDViN [60]
3 years ago
10

Explain why a stopclock will give a poor result in a instanteouse speed experiment

Physics
1 answer:
Arturiano [62]3 years ago
7 0
It takes a while to stop it
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Is salt an element or a compound
LiRa [457]

Hello!

To answer your question, salt is a compound!

It is the product of the chemical bond between Na (Sodium) and Cl (Chloride),

Hopes this help you with your question.

5 0
4 years ago
Out of these people who r ur favs?
pav-90 [236]

Answer:

Is it a sin to like them all...? haha

4 0
4 years ago
Read 2 more answers
Roxy is driving down East Capitol Street. She drives 1380 meters in 45 seconds. Assuming she does not speedup or slow down, what
Natasha_Volkova [10]

Answer:

30.66667

Explanation:

should be the answer if the calculator is correct

7 0
3 years ago
A sample of ore containing radioactive strontium 38Sr90 has an activity of 8.2 × 105 Bq. The atomic mass of strontium is 89.908
ahrayia [7]

From the activity values and the decay constant, the mass of of Strontium in the sample is:

1.62 × 10^{-7}g

<h3>What is the decay constant of an element?</h3>

The decay constant of an element is the probability of decay of a nucleus per unit time.

{λ = ln 2 / t1/2 

where;

t1/2 is the half-life of the isotope.

The half-life is converted to seconds since the decay constant is asked in per seconds.

28.8 years = 28.8 × 3.156 × 10^{7} = 908928000 s \\

Hence;

λ = \frac{ln2}{90892800s} = 7.626 s^{-1}

                                       

The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:

  • A = (–) λN

N = \frac{8.25 ×10^{5}}{7.626×10^{-10}} = 1.082 × 10^{15}              

Molar mass of Strontium-90 is 90 g.

1 mole of Strontium-90 contains 6.02×10^23 nuclei.

The mass, m of Strontium in the sample is calculated:

m = 1.082 × 10^{15} × \frac{90 g}{6.02 × 10^{23}} = 1.62 × 10^{-7}g \\

Therefore, the mass of of Strontium in the sample is:

1.62 × 10^{-7} \: g

Learn more about decay constant at: brainly.com/question/17159453

5 0
3 years ago
Let T be a linear transformation from a vector space V with dimension 11 onto a vector space W with dimension 7. What is the dim
erica [24]

Answer:

The dimension of the nullspace of T = 4

Explanation:

The rank/dimension theorem is explains that:

Suppose V and W are vector spaces over F, and T:V → W is linear. If V is finite dimensional, then

nullity(T) + rank(T) = dim(V).

rank(T) = dimension of T = dim(T) = dim(W) = 7

nullity(T) = dimension of the nullspace of T = dim(T) = ?

dim(V) = 11

nullity(T) = dim(V) - dim(T) = 11 - 7

nullity(T) = 4.

8 0
3 years ago
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