Question

How many grams of NaHCO3 would you need to react with 6 moles of H2SO4?

Answer 1

Answer:

$\boxed{\text{1000 g}}$

Explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                           84.01  

              H₂SO4 + 2NaHCO₃ ⟶ Na₂SO₄ + 2CO₂ + 2H₂O

n/mol:         6

1. Use the molar ratio of NaHCO₃ to calculate the moles of NaHCO₃.

$\text{Moles of NaHCO _{3} = 6 mol H _{2} SO _{4} } \times \dfrac{\text{2 mol NaHCO _{3} }}{\text{1 mol H _{2} SO _{4} }}\\=\text{12 mol NaHCO _{3} }$

2. Use the molar mass of NaHCO₃ to calculate the mass of NaHCO₃.

$\text{Mass of NaHCO _{3} = 12 mol NaHCO _{3} } \times \dfrac{\text{84.01 g NaHCO _{3} }}{\text{1 mol NaHCO _{3} }}\\\\= \text{1000 g NaHCO _{3} }$

You must use $\boxed{\textbf{1000 g}}$ of NaHCO₃.