Question

A body undergoing a uniformly, acceleraten motion has

Answer 1

Answer:

$2 m/s^2$

Explanation:

The acceleration of an object is given by:

$a=\frac{v-u}{\Delta t}$

where

v is the final velocity

u is the initial velocity

$\Delta t$ is the time interval

For the body in the problem, we have:

$u=10 m/s$ at t = 1 s

$v=48 m/s$ at t = 20 s

So the time interval is

$\Delta t = 20 -1 = 19 s$

And so, the acceleration is

$a=\frac{48-10}{19}=2 m/s^2$