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2 years ago

How many grams of oxygen are in 50.00 g of sucrose? Show your work

Chemistry

2 answers:

Scilla [17]2 years ago

5 0

Let f(x) = x2 − 16. Find f−1(x)

Marta_Voda [28]2 years ago

3 0

Just find the percent mass of oxygen in sucrose again. and then multiply that by 50.00.

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A bell hanging at the top of a tower has 8,550 j of energy. If it has a mass of 20 kg find the height of the Bell

kogti [31]

43.62m

Explanation:

Given parameters:

Energy = 8550J

Mass of bell = 20kg

Unknown:

Height of the bell = ?

Solution:

As this state, the bell possesses potential energy. Potential energy is the energy at rest in a body. It is due to the position of the body.

Potential energy = m g h

m is the mass of the body

g is the acceleration due to gravity of the body

h is the height of the body

The unknown is h and we should solve for it.

g = 9.8m/s²

Input the variables;

8550 = 20 x 9.8 x h

h = 43.62m

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

3 0

2 years ago

What volume of a 2.10 M NaCl solution is

cluponka [151]

Answer:

146.3g NaCl (mol NaCl/58.44g NaCl) = 2.50 mol NaCl

1.5M NaCl = 1.5 mol NaCl / 1 L = 2.5 mol NaCl / x L, solve for x

x L = 2.5 mol NaCl / 1.5 mol NaCl = 1.66 L

It gives the answer and all the working.

To put it another way:

Dividing the amount required by the molar mass

we quickly see that 2.5 moles are required.

One litre of 1.5 molar solution gives 1.5 moles

we need a further mole, which is 2/3 of 1.5 so 2/3 of a litre.

3 0

2 years ago

A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.

Alexxandr [17]

Answer: The empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

Explanation:

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = $\frac{0.313}{0.078}=4.01\approx 4$

For Hydrogen = $\frac{0.316}{0.078}=4.05\approx 4$

For Oxygen = $\frac{0.078}{0.078}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is $C_4H_4O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

$n=\frac{130g/mol}{68g/mol}=1.9\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2$

Hence, the empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

4 0

3 years ago

Which group 1 metal and group 2 non metal would react together most?

Talja [164]

Answer:

Potassium and oxygen

Explanation:

3 0

2 years ago

How many kilograms are in 6.983 moles of baking soda (NaCHO3)?

nasty-shy [4]

It should be about 0.586620881 kilograms

6 0

3 years ago