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Jobisdone [24]
2 years ago
11

How many grams of oxygen are in 50.00 g of sucrose? Show your work

Chemistry
2 answers:
Scilla [17]2 years ago
5 0
<span>Let f(x) = x2 − 16. Find f−1(x)</span>
Marta_Voda [28]2 years ago
3 0
Just find the percent mass of oxygen in sucrose again. and then multiply that by 50.00.
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If you are given only the mass number of neutrons, how do we find an atomic number?
77julia77 [94]

Mass number is the sum of protons and neutrons.

Atomic number is the total number of protons present.

Mass number = protons + neutrons

Atomic number = protons present.

From the above equations we can conclude that,

Atomic number= Mass number- neutrons.

Thus we can find out the atomic number by subtracting the number of neutrons from the mass number.

3 0
2 years ago
Read 2 more answers
Why must there be two chlorine atoms for every one calcium atom
Nady [450]

Answer:

There must be two Chlorine atoms for every one Calcium atom in order to fulfill Chlorine's octet rule and pair Calcium's unpaired electrons.

Explanation:

Calcium has two unpaired electrons in its Lewis dot structure, while Chlorine has one unpaired electron.

<em>So why can't we just make a double bond for </em><em>one</em><em> Chlorine?</em>

Chlorine has seven valence electrons, so once it shares electrons with Calcium, the octet rule is accomplished, and no more pairs can be made.

4 0
3 years ago
Non-renewable energy is often called?​
DIA [1.3K]

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It is also called a finite resource

Explanation:

5 0
3 years ago
How far apart must two point charges of 75.0 nC (typical of static electricity) be to have a force of 1.00 N between them? (answ
Jet001 [13]

Answer:

7.12 mm

Explanation:

From coulomb's law,

F = kqq'/r².................... Equation 1

Where F = force, k = proportionality constant, q and q' = The two point charges, r = distance between the two charges.

Make r the subject of the equation,

r = √(kqq'/F).......................... Equation 2

Given: q = q' = 75.0 nC = 75×10⁻⁹ C, F = 1.00 N

Constant: k = 9.0×10⁹ Nm²/C².

Substitute into equation 2

r = √[ (75×10⁻⁹ )²9.0×10⁹/1]

r = 75×10⁻⁹.√(9.0×10⁹)

r = (75×10⁻⁹)(9.49×10⁴)

r = 711.75×10⁻⁵

r = 7.12×10⁻³ m

r = 7.12 mm

Hence the distance between the point charge = 7.12 mm

3 0
3 years ago
If one parent has sickle cell anemia and the other parent is a carrier, what is the possibility that their child will have sickl
earnstyle [38]
It’s a 50 50 chance unless one parent has a dominate gene
5 0
3 years ago
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