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Anna007 [38]
3 years ago
12

1) A U-tube, in which both ends are open to the atmosphere, is partially filled with water. Oil which does not mix with water is

poured into one side of the tube until it stands a distance d=12.3 mm above the water level on the other
side which has meanwhile risen a distancea=67.5 mm from its original level Find the density of the oil
2) The mercury column in a barometer has a measured height h of 740.35 mm. the temperature is-5.0 C
which temperature the density of mercury is 1.3608 104 kg/m3. the free-fall acceleration at the site of the
barometer is 9.7835 m/s2. What is the atmospheric pressure?​

Physics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

1) 916 kg/m³

2) 9.8566×10⁴ Pa

Explanation:

1) Originally, the water is at the same level on both sides.  When the oil is added, one side goes down 67.5 mm and the other side goes up 67.5 mm.  The top of the oil is 12.3 mm above the water, so the total height of the oil relative to the low end of the water is:

12.3 mm + 67.5 mm + 67.5 mm = 147.3 mm

And the height of the water relative to the low end is:

67.5 mm + 67.5 mm = 135 mm

The pressure at the bottom of the oil equals the pressure of the water at the same elevation.

P = P

ρgh = ρgh

ρh = ρh

ρ (147.3 mm) = (1000 kg/m³) (135 mm)

ρ = 916 kg/m³

2) P = ρgh

P = (1.3608×10⁴ kg/m³) (9.7835 m/s²) (0.74035 m)

P = 9.8566×10⁴ Pa

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How much force is required to move a electron through an electric field with strength of 1.375 x 10^19 N/C?
Luda [366]

Answer:

The magnitude of the force required to move the electron through the given field is 2.203 N

Explanation:

Given;

The field strength of the electron, E = 1.375  x 10¹⁹ N/C

charge of electron, q = 1.602 x 10⁻¹⁹ C

The magnitude of the force required to move the electron through the given field is calculated as follows;

F = Eq

F = (1.375  x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)

F = 2.203 N

Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N

4 0
3 years ago
A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the
sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg

Since the frictional force f_k is equal to f_k=\mu_k N=\mu_k mg, then we have that the acceleration is:

a=\frac{\mu_k mg}{m}=\mu_k g

Now, from the definition of acceleration we get:

a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}

And, as the final velocity is zero because the box gets to a stop, we have:

t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}

Finally, we calculate the displacement:

x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm

This means that the box moves 7.29cm backwards relative to the belt.

4 0
3 years ago
Why is ammeter connected in series in an electric circuit?
topjm [15]
In order to measure the size of the electrical current flowing in the circuit,
the current must pass through the meter.
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Which change indicates that the universe is expanding?
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5 0
3 years ago
Read 2 more answers
How do I solve this step by step? I’m really confused
LekaFEV [45]

Step-#1:

Ignore the wire on the right.

Find the strength and direction of the magnetic field at P,

caused by the wire on the left, 0.04m away, carrying 5.0A

of current upward.

Write it down.


Step #2:

Now, ignore the wire on the left.

Find the strength and direction of the magnetic field at P,

caused by the wire on the right, 0.04m away, carrying 8.0A

of current downward.

Write it down.


Step #3:

Take the two sets of magnitude and direction that you wrote down

and ADD them.


The total magnetic field at P is the SUM of (the field due to the left wire)

PLUS (the field due to the right wire).


So just calculate them separately, then addum up.

4 0
3 years ago
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