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Lilit [14]
3 years ago
6

You perform an experiment using 8.0 m hcl. And 2.4 m naoh. The experiment calls for 5.0 ml of hcl and 20.0 ml of naoh. How many

moles of nacl are produced from this reaction?
Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

2.34g of NaCl

Explanation:

HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)

Number of moles of HCl= 8 × 5/1000= 0.04 moles

Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles

HCl is the limiting reactant

From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl

0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl

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A sample of gas occupies 10.0 L at 240°C under a pressure of
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