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Lilit [14]
3 years ago
6

You perform an experiment using 8.0 m hcl. And 2.4 m naoh. The experiment calls for 5.0 ml of hcl and 20.0 ml of naoh. How many

moles of nacl are produced from this reaction?
Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

2.34g of NaCl

Explanation:

HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)

Number of moles of HCl= 8 × 5/1000= 0.04 moles

Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles

HCl is the limiting reactant

From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl

0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl

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Be sure to answer all parts. part 1 out of 4 how many nucleophilic centers are present in methanol (ch3oh)?
leva [86]

Answer:

              One nucleophilic center

Explanation;

Nucleophile:

                    Nucleophile is a substance which is nucleus loving in nature (<em>Nucleo</em>; Nucleus , <em>phile</em>; Loving). It is known as a specie which donates a lone pair of electrons to electrophile (electron loving) in a chemical reaction.

                    Thus, Nucleophile is the region of higher electron density in a molecule and attacks on the lower electron density region of another molecule. Also, the nucleophile can also contain a negative charge.

Number of Nucleophilic centers in Methanol:

The chemical structure of Methanol is attached below and it can be observed that the oxygen atom is containing two lone pair of electrons. Hence, the oxygen atom can act as a nucleophilic center. Therefore, there is only one nucleophilic center in methanol.

                        H₃C-OH  +  H₃C-Br     →        H₃C-O-CH₃  +  HBr

In above reaction methanol is acting as a nucleophile and is attacking on electrophilic center (Carbon) of methyl bromide yielding dimethyl ether.

8 0
3 years ago
Read 2 more answers
What is AgNO3 + KCI-KNO3+AgCI. What type of reaction does this represent
PIT_PIT [208]
<span>C4H10 + 6.5 O2 ----> 4CO2 + 5H2O 

2C4H10 + 13 O2 ----> 8CO2 + 10H2O 

1. Count the C on the left (4), put a 4 where the C on the right. 

2. Count the H on the left (1), you have two on the right, so you multimply this two by 5. Put the 5 in front of the H2O 

3. Count the O on the right. You have 4*2 + 5 = 13. You have two on the left, so you need 6.5 on the left. 

4. Now multiply everything on the equation by two so you have nice integer numbers. 

5. check you have the same amount of everything on each side. 
Example C: left 8, right 8, etc.
I hope this helps. :)</span><span>
</span>
6 0
3 years ago
When parallel light rays exit a concave lens,the light ray is?
ad-work [718]
When parallel rays exit a concave lens, the light rays are divergent.
The rays diverge or bend away from the axis it has been traveling upon entering the lens when it reaches the other side of the lens. These rays appear to have come from the same focal point before entering the concave lens. When these parallel rays are extended, it will be traced back to a single point of origin.
5 0
3 years ago
Read 2 more answers
__ SnCl4 → __ Sn + __ Cl2
Kisachek [45]

Answer:

Sn (s) + 2 Cl2 (g) → SnCl4 (l)

This is an oxidation-reduction (redox) reaction:

4 Cl0 + 4 e- → 4 Cl-I

(reduction)

Sn0 - 4 e- → SnIV

(oxidation)

Cl2 is an oxidizing agent, Sn is a reducing agent.

Reactants:

Sn

Names: Tin source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Sn source: wikidata, accessed: 2019-09-07, Element 50 source: wikidata, accessed: 2019-09-07

Appearance: White crystalline powder source: ICSC, accessed: 2019-09-04; Gray to almost silver-white, ductile, malleable, lustrous solid. source: NIOSH NPG, accessed: 2019-09-02

Cl2

Names: Chlorine source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Molecular chlorine source: NIOSH NPG, accessed: 2019-09-02

Appearance: Greenish-yellow compressed liquefied gas with pungent odour source: ICSC, accessed: 2019-09-04; Greenish-yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.] source: NIOSH NPG, accessed: 2019-09-02

Products:

SnCl4 – Tetrachlorostannane source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02, Tin tetrachloride source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Tin(IV) chloride source: wikipedia, accessed: 2019-09-28

Other names: Stannic chloride source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Tin(iv) chloride (anhydrous) source: ICSC, accessed: 2019-09-04

Appearance: Colorless to slightly yellow fuming liquid source: wikipedia, accessed: 2019-09-28; Colourless or slightly yellow fuming liquid with pungent odour source: ICSC, accessed: 2019-09-04

6 0
2 years ago
When a student chemist transferred the metal to the calorimeter, some water splashed out of the calorimeter. will this technique
Natalka [10]

Answer:

It will be reported too low.

Explanation:

To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.

Qmetal + Qwater = 0

Qmetal = -Qwater

The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:

m_metal*s*ΔT_metal = - m_water *c*ΔT_water

s = -m_water *c*ΔT_water / m_metal*ΔT_metal

So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.

5 0
3 years ago
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