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Lilit [14]
3 years ago
6

You perform an experiment using 8.0 m hcl. And 2.4 m naoh. The experiment calls for 5.0 ml of hcl and 20.0 ml of naoh. How many

moles of nacl are produced from this reaction?
Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

2.34g of NaCl

Explanation:

HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)

Number of moles of HCl= 8 × 5/1000= 0.04 moles

Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles

HCl is the limiting reactant

From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl

0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl

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4 0
3 years ago
The following balanced equation describes the reduction of iron(III) oxide to molten iron within a blast furnace: Fe2O3(s) + 3CO
Irina-Kira [14]

Answer:

Amount of excess Carbon (ii) oxide left over = 23.75 g

Explanation:

Equation of the reaction: Fe₂O₃ + 3CO ----> 2Fe + 3CO₂

Molar mass of Fe₂O₃ = 160 g/mol;

Molar mass of Carbon (ii) oxide = 28 g/mol

From the equation of reaction, 1 mole of Fe₂O₃ reacts with 3 moles of carbon (ii) oxide; i.e. 160 g of iron (iii) oxide reacts with 84 g (3 * 28 g)  of carbon (ii) oxide

450 g of Fe₂O₃ will react with 450 * 84/180) g of carbon (ii) oxide = 236..25 g of carbon (ii) oxide

Therefore the excess reactant is carbon (ii) oxide.

Amount of excess Carbon (ii) oxide left over = 260 - 236.25

Amount of excess Carbon (ii) oxide left over = 23.75 g

5 0
3 years ago
In the disproportionation reaction CI2 + H2Omc021-1.jpgHCIO + HCI, what describes the oxidation states of the substance Cl?
Sophie [7]
<span>Reaction: CI2 + H2O    ---->  HCIO + HCI

Oxidations states:

The oxitation state of Cl2 = 0, because the oxidation state of an atom alone or a molucule with one kind of atom is always 0.

The oxidation state of Cl in HClO is +1 because the oxidation state of H is + 1, the oxidation state of O is - 2, and the molecule is neutral, so  +1 + 1 - 2 = 0

The oxidation state of Cl in HCl is - 1, because the oxidation state of H is +1 and the molecule is neutral, so - 1 + 1 = 0.

Also, you shall remember that when an atom increases its oxidation state is is oxidized and when an atoms reduces its oxidations state it is reduced.

With that you conclude that the right option is the last statement: </span>Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation number +1 in HClO.
8 0
4 years ago
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