Question

You perform an experiment using 8.0 m hcl. And 2.4 m naoh. The experiment calls for 5.0 ml of hcl and 20.0 ml of naoh. How many moles of nacl are produced from this reaction?

Answer 1

Answer:

2.34g of NaCl

Explanation:

HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)

Number of moles of HCl= 8 × 5/1000= 0.04 moles

Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles

HCl is the limiting reactant

From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl

0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl