Answer:
KNO3- Potassium Nitrate, KOH- Potassium hydroxide, K2CRO4- Potassium chromate
Explanation:
Answer:
1.47 atm
Explanation:
Step 1: Calculate the moles corresponding to 41.6 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
41.6 g × 1 mol/32.00 g = 1.30 mol
Step 2: Convert 30.0 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 30.0 + 273.15 = 303.2 K
Step 3: Calculate the pressure exerted by the oxygen
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 1.30 mol × (0.0821 atm.L/mol.L) × 303.2 K / 22.0 L = 1.47 atm
Use the formula (P1V1)/T1 = (P2V2)/T2
(12.8 * 100)/(-108 + 273) = (.855 * P2)/(22 + 273) Need to convert Celsius into Kelvins
1280/165 = (0.855 * P2)/295
7.755556 = 0.002898 * P2
P2 = 2676.18 kPa
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Answer:
The electric force is conservative.
Since
ΔK = −ΔU,
Kf − Ki =Ui −Uf.
We have,
Kf = 0
Ui = 0.
Thus Ki =Uf.
<u>so ,at 10 fm Uf = (2×10)−12 J.</u>
Answer:
Explanation:
Mg²⁺ is divalent , hence
Molecular weight / 2 = equivalent weight .
.25 moles = 2 x .25 equivalents = .5 equivalents .
Cl⁻ is monovalent so
molecular weight = equivalent weight
.50 mole = .50 equivalent
Total equivalent = .50 of Mg²⁺ + .50 of Cl⁻
= 1 equivalent .
