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SOVA2 [1]
3 years ago
10

The amount of heat required to melt lead at it melting temperature is 23.0 kJ/kg. The amount of heat required to melt mercury at

its melting temperature is 11.4 kJ/kg. What is the effect of adding 24 kJ of thermal energy to 1 kg of mercury and lead when each have just reached their melting temperatures?
The addition of 24 kJ of energy will allow all of the mercury and lead to change from solid to liquid. The temperature of each substance will also increase.

The addition of 24 kJ of energy will allow all of the mercury and lead to change from solid to liquid. The temperature of each substance will not change.

The addition of 24 kJ of energy will allow all of the mercury to change from solid to liquid, and some of the lead to change from solid to liquid. Only the temperature of the mercury will increase.

The addition of 24 kJ of energy will allow all of the mercury and lead to change from liquid to gas. The temperature of each substance will increase.
Physics
2 answers:
svet-max [94.6K]3 years ago
4 0

The addition of 24 kJ of energy will allow all of the mercury and lead to change from solid to liquid. The temperature of each substance will also increase.

GarryVolchara [31]3 years ago
3 0

the addition of 24 kj of energy will allow all of the mercury and lead to change from solid to liquid. the temperature of each substance will also increase.

this is the answer as i did the exam and got it right!! thanks to the other person

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A particle has charge -1.95 nC. (a) Find the magnitude and direction of the electric field due to this particle at a point 0.225
11Alexandr11 [23.1K]

Answer:

a)

346.67 N/C, downward

b)

1.3 m

Explanation:

(a)

q = magnitude of charge on the particle = 1.95 x 10⁻⁹ C

r = distance of location from the charged particle = 0.225 m

E = magnitude of electric field at the location

Magnitude of electric field at the location is given as

E = \frac{kq}{r^{2}}

Inserting the values

E = \frac{(9\times 10^{9})(1.95 \times 10^{-9})}{(0.225)^{2}}

E = 346.67 N/C

a negative charge produce electric field towards itself.

Direction :  downward

(b)

E = magnitude of electric field at the location = 10.5 N/C

r = distance of location from the charged particle = ?

q = magnitude of charge on the particle = 1.95 x 10⁻⁹ C

Magnitude of electric field at the location is given as

E = \frac{kq}{r^{2}}

Inserting the values

10.5 = \frac{(9\times 10^{9})(1.95 \times 10^{-9})}{r^{2}}

r = 1.3 m

5 0
3 years ago
A 1.50-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Ignore the ve
Natalka [10]

Answer:

Explanation:

mass of string = .0125 / 9.8

= 1.275 x 10⁻³ kg

Length of string l = 1.5 m .

m = mass per unit length

= ( .1.275 / 1.5) x 10⁻³ kg/m

m = .85 x 10⁻³ kg/m

wave equation: y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

compare with equation of wave

y(x,t) = Acos(K x − ω t)

ω ( angular velocity ) = 4830 rad/s

k = 172 rad/m

Velocity = ω / k

= 4830/172 m /s

= 28.08 m /s

velocity of wave = \sqrt{\frac{W}{m } }

28.08 = \sqrt{\frac{W}{.85\times10^{-3} } }

788.48 =  W / .85 X 10⁻³

W = 670 x  10⁻³ N .

c ) wave length

wave length =2π  / k

= 2 x 3.14 / 172

= .0365 m

no of wave lengths over whole length of string

= 1.5 / .0365

= 41

d )

equation for waves traveling down the string

= (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

5 0
3 years ago
Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Eart
Whitepunk [10]

The correct options are:

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

<h3>Why do we radio waves over other electromagnetic waves to transmit information to Earth? </h3>

Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.

Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.

Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.

With that in mind, the correct options are.

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

These are the two main reasons of why we use radio waves.

If you want to learn more about electromagnetic waves.

brainly.com/question/14015797

#SPJ1

4 0
2 years ago
A series circuit is composed of two resistors:
WITCHER [35]
<h3>Answer:</h3>

1.3 Amps

<h3>Explanation:</h3>

<u>We are given;</u>

A circuit with resistors, R1 and R2

R1 = 7 Ω

R2 = 11 Ω

Voltage = 24 V

We are required to calculate the current in the circuit.

<h3>Step 1: We need to find the effective resistance.</h3>

When resistors are arranged in series, the effective resistance is calculated by;

Rt = R₁ + R₂ + R₃ + ..........Rₙ

Therefore;

Total resistance = 7 + 11

                          = 18 Ω

<h3>Step 2: Calculate the current in the circuit</h3>

From the ohm's law;

V = IR

Rearranging the formula;

I = V/R

Thus;

I = 24 V ÷ 18 Ω

 = 1.333 Amps

= 1.3 Amps

Thus, the current in the circuit is 1.3 Amps

7 0
3 years ago
The top of lake is frozen as atmospheric temperature is -10 degree Celsius the temperature of the bottom of the lake is most lik
hjlf

4°Celcius Water is densest at 4°C

4 0
3 years ago
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