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Olin [163]
3 years ago
10

How many significant numbers are in 2.03?

Chemistry
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

2 and 1 are sig figs.

Explanation:

any number that is not zero is a sig fig (exceptions do apply)

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The isotope of hydrogen that has two neutrons is called A. hydrogen. B. deuterium. C. tritium. D. dihydrogen.
lutik1710 [3]

Answer:

C.Tritium

Explanation:

Isotopes are forms of an element with different mass number but same atomic number. Mass number is the sum of the number of protons and neutrons in the nucleus of an atom, while atomic number is the number of protons.

Mass number = protons +neutrons.

Atomic number = protons only

We can say that mass number = atomic number + number of neutrons.

The number of neutrons is what differentiates the isotopes of an element.

For hydrogen element, it has three isotopes namely; protium, deuterium and tritium which have 0,1 and 2 neutrons respectively. Thus the answer is C

7 0
3 years ago
What properties of salt water make it easy to separate the salt from the water?
11Alexandr11 [23.1K]
Salt is a non magnetic solid which makes it soluble in water. 
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3 0
3 years ago
A system being studied in a 3.0-liter reactor was charged with 0.150 moles of H2, 0.150 moles of X2, and 0.600 moles of HX. A ca
ycow [4]

Answer:

The reaction is not in equilibrium and it proceed in reverse direction to reach the equilibruim condition

Explanation:

We have

H₂(g) + x₂(g)  ⇆  2HX (g)

Kc = 2.4 x 10 ⁻³ at 25°C

K_c = \frac{[HX]^2}{[H_2][X_2]}

Now we have 3L reactor and the number of mole of species are 0.150 mole H₂, 0.150 mole X₂ and 0.600 mole HX

Therefore,

[H_2] = \frac{0.150}{3} \\= 0.05M

[X_2] = \frac{0.150}{3} \\= 0.05M

[HX] = \frac{0.600}{3} \\= 0.2M

Therefore,

Q_c = \frac{[HX]^2}{[H_2][X_2]}

Q_c = \frac{[0.200]^2}{[0.05][0.05]}\\\\=16

Now, we calculate the free energy change for the reaction

ΔrG = RT In Q/K

= (8.314) \times (298) \times In (\frac{16}{2.4\times 10^-^3} )\\\\=+21814.7 J/mol

As free energy is +ve so the reaction is not in equilibruim and proceed in reverse reaction to reach tje equilibruim condition

8 0
3 years ago
The "fatal flaw" in Rutherford's model of the atom, which was corrected by Bohr's model, was the idea that, if the electrons wer
Gennadij [26K]

The answer is

A. orbiting the nucleus, changing direction and thus giving off energy, the electrons would lose all energy and collapse into the nucleus.

Bohr stated that electron can be only on certain distances from nucleus. Electrons can be only on allowed orbits.

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3 years ago
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Answer:

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