Respuesta:
24m
Explicación:
Según la ecuación de movimiento
v = u + en
Dado
Velocidad final v = 12 m / s
velocidad inicial u = 0 m / s
tiempo t = 4s
Sustituir
12 = 0 + 4a
a = 12/4
a = 3 m / s²
Lo siguiente es obtener la distancia;
S = ut + 1 / 2at²
S = 0 (4) + 1/2 (3) (4) ²
S = 3 * 16/2
S = 48/2
S = 24 m
Por lo tanto, la distancia requerida es de 24 m.
Consider velocity to the right as positive.
First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right
Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left
Total momentum of the system is
P = m₁v₁ + m₂v₂
= 4*2 + 8*(-3)
= -16 (kg-m)/s
Let v (m/s) be the velocity of the center of mass of the 2-block system.
Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s
Answer:
The center of mass is moving at 1.33 m/s to the left.
