Answer : The volume of mixture is, 4.99 liters.
Explanation :
First we have to calculate the moles of and .
As we know that at STP, 1 mole of substance contains 22.4 L volume of substance.
As, 22.4 L volume of present in 1 mole of
So, 5 L volume of present in mole of
And,
As, 22.4 L volume of present in 1 mole of
So, 3 L volume of present in mole of
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.223 moles of react with moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 2 mole of
So, 0.223 moles of react to give 0.223 moles of
Now we have to calculate the volume of .
As, 1 mole of gas occupy 22.4 L volume of
So, 0.223 mole of gas occupy volume of
Therefore, the volume of the mixture is 4.99 liters.