600. I forgot the measurement. but 600 is correct
The capacitance of a parallel-plate capacitor in vacuum is given by
where
A is the area of each plate
d is the separation between the plates
is the electric permittivity in vacuum
For the capacitor in our problem, the plates are circular, with a diameter of d=4.0 cm, so their radius is r=2.0 cm=0.02 m and their area is
while the separation between the plates is
Therefore the capacitance is
I believe the answer is hertz.
Answer:
<h2>300 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 2 × 10 × 15
We have the final answer as
<h3>300 J</h3>
Hope this helps you