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Marina86 [1]
3 years ago
10

The table lists several radioisotopes that have technological uses. Which radioisotope would be used by both archaeologists and

botanists (scientists who study plants)? uranium-238 carbon-14 iodine-131 technetium-99
Physics
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

B. carbon-14

Explanation:

Vinil7 [7]3 years ago
5 0
Carbon-14
Since carbon can be found in plants and items that are studied by archaeologist 
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Which applications, either for diagnostic purposes or for therapeutic purposes, involve radioactive materials placed in the body
CaHeK987 [17]

When a radioactive material is required to be placed in the body, the applications are brachytherapy and radioisotope imaging.

Radioactive materials are elements which has the ability to disintegrate by emitting radioactive substance or radiation. A good example of this is Cobalt-60, Titanium-99 etc.

Brachytherapy is a therapeutic process in which radioactive material is inserted into the body in close proximity to the region affected. The radioactive material emits radiations which are required to control the unwanted biological material in the body. A good application of this is the treatment of cancer using Cobalt-60.

Radioisotope imaging is a diagnostic process which is an imaging technique that may require placing a radioactive material in the body so as to trace or locate the affected part of the body. In this case, the material is used as a tracing element.

The applications that require the placing of radioactive materials in the body are brachytherapy and radioisotope imaging.

For more explanation, visit: brainly.com/question/9790340

5 0
3 years ago
Read 2 more answers
A fanis rotating at a constant 360.0 rev/min. What is the magnitude of the acceleration of a point on one of its blades 10.0 cm
Mariana [72]

Answer:

142m/s2

Explanation:

The solution is in the attached file below

4 0
3 years ago
A block is projected up a frictionless inclined plane with initial speed v0 = 7.14 m/s. The angle of incline is θ = 36.5°. (a) H
Wewaii [24]

Answer:

(a)x=4.37m\\\\(b)t=1.225s\\\\(c) v_{f}=7.14m/s

Explanation:

Given data

v_{o}=7.14m/s\\\alpha =36.5^o

For Part (a)

Starting with the -ve acceleration of the body (opposite to the gravitational force)

a=-gSin\alpha \\a=-(9.8m/s^2)Sin(36.5)\\a=-5.83m/s^2

Using equation of motion

v_{f}^2=v_{o}^2+2ax\\(0m/s)^2=(7.14m/s)^2+2(-5.83m/s^2)x\\-(7.14m/s)^2=2(-5.83m/s^2)x\\x=\frac{-(7.14m/s)^2}{2(-5.83m/s^2}\\ x=4.37m

For Part (b)

Using the result in Part (a) we can substitute in other equation of motion to get time t:

x=\frac{1}{2}vt\\ 4.37m=\frac{1}{2}(7.14m/s)t\\ (7.14m/s)t=2*(4.37)\\t=8.744/7.14\\t=1.225s

For Part (c)

At state 2 where vo=0m/s and the acceleration is positive (same direction as the gravitational force)

a=gSin\alpha \\a=(9.8m/s^2)Sin(36.5)\\a=5.83m/s^2\\\\\\v_{f}^2=v_{o}^2+2ax\\v_{f}^2=(0m/s)^2+2(5.83m/s^2)(4.37m)\\v_{f}^2=50.95\\v_{f}=\sqrt{50.95}\\ v_{f}=7.14m/s

4 0
3 years ago
We say that visible light has wavelength from 400nm to roughly 800nm. What is the biggest "energy-jump" (excited) for an atom if
icang [17]

Answer:

4.98\cdot 10^{-19} J

Explanation:

The energy of the emitted photon is inversely proportional to its wavelength, according to the equation:

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34} Js is the Planck's constant

c=3.0\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

This means that the biggest energy is released when the wavelength is the shortest. For a photon of visible light, the shortest wavelength is

\lambda=400 nm = 400\cdot 10^{-9} m

So, substituting into the equation, we find the corresponding energy:

E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.98\cdot 10^{-19} J

6 0
4 years ago
5. The value of a car decreases by 15% each
Kazeer [188]

Answer:

the car is worth $2,400

Explanation:

6000*15%=900

900*4=3600

6000-3600=2400

6 0
3 years ago
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