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aleksandr82 [10.1K]
3 years ago
14

so classmate states that continental drift could not be possible because it would take far too much force to move tectonic plate

s. Describe the hypothesis scientists use to explain the movement of tectonic plates. Which hypothesis do many scientists think may explain the great force needed to move plates?
Physics
1 answer:
Juliette [100K]3 years ago
5 0
Any student who states that tectonic plates are too massive to move doesn't understand how much heat exists in the center of the earth. This heat is capable of moving the most massive of plates.
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two masses are separated by 1 m. suppose the masses are moved so they are 2 m apart how will the gravitational force change
Verdich [7]
The gravitational force would get stronger because the farther the two masses are separated the more gravitational force will be used to pull them together the closer they are the less gravitational pull is used to pull them together
5 0
3 years ago
Energy of motion is.
lidiya [134]
The answer is C. Potential energy is when an object is at rest.
Kinetic is when an object is in motion.
5 0
3 years ago
Read 2 more answers
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

\rho(r) = ar^2 - br^3

r is the radius of the spherical shell

dr is the thickness

volume of shell

dV = 4 \pi r^2 dr

mass of shell

dM = \rho(r)dV

\rho = \rho_0 - br

now,

dM = (\rho_0 - br)(4 \pi r^2)dr

integrating both side

M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr

M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})

M = \pi R^3(\dfrac{\rho_0}{3}+\rho)

we know,

a = \dfrac{GM}{R^2}

a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}

a =\pi RG(\dfrac{\rho_0}{3}+\rho)

a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)

a = 9.94 m/s²

7 0
2 years ago
A 49 N coconut is in a 15 m tree. What is te potential energy of the coconut?
eduard

Answer:

735 J

Explanation:

From the question given above, the following data were obtained:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:

Potential energy = weight × height

With the above formula, we can obtain the potential energy of the coconut as follow:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy = weight × height

Potential energy = 49 × 15

Potential energy = 735 J

Thus, the potential energy of the coconut is 735 J

4 0
2 years ago
The Bugatti Chiron is currently the fastest production car in the world reaching a top speed of 261 mph
VMariaS [17]

Answer:304 not 261

Explanation:

That is, in prototype form anyway – the custom Chiron Longtail hit 304 mph (490 km/h) last year, but the production version dubbed the Chiron Super Sport 300+ will be electronically limited to only 273 mph (440 km/h).

...

7 0
2 years ago
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