In 1 mol of CH3OH, you have 4 H-atoms (because 3 H-atoms
are attached to the C-atom, and one H-atom in the OH group). That means
in 0.500 mol of CH3OH, you have 2 H-atoms since it is halved. And then we have Avogadro's constant: 6.02 * 1023.
The question asks for how many hydrogen atoms there are in 0.500 mol CH3OH. Using the numbers that we have (Avogadro's constant and no. of H-atoms), the answer of the question will be something like:
<span>H-atoms in CH3OH = 2 * 6.02 * </span>1023<span> = ~1.2 * 10</span>24
Explanation:
We know that,
Energy = .......... (1)
and, Energy = ............ (2)
Now, equating both equations (1) and (2) as follows.
=
v =
=
=
= m/s
or, = 18 km/s
Thus, we can conclude that initial speed the electron must have in order to reach an infinite distance from the sphere and have zero kinetic energy when it gets there is 18 km/s.
Answer:
σ*2pₓ, also called
Explanation:
I have drawn the MO diagram for fluorine below.
Each F atom contributes seven valence electrons, so we fill the MOs of fluorine with 14 electrons.
We have filled the and MOs.
They are the highest occupied molecular orbitals (HOMOs).
The next unfilled level (the LUMO) is the σ*2pₓ orbital. If you use the symmetry notation, it is called the orbital.
This is the orbital that fluorine uses when it acts as an electron acceptor.
Answer: 137.16
Explanation: there are 91.44 cm in one yard so i multiplied 91.44 by 1.5