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timofeeve [1]
3 years ago
15

Organ system that is responsible for breaking down food

Physics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:

A. Digestive

Explanation:

VLD [36.1K]3 years ago
4 0

Answer:

digestive system

Explanation:

since the digestive system secretes enzymes like amylase,lipase etc. required by the body for the proper breakdown of food.

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Explain the immediate impact of a catastrophic event
exis [7]
Any event<span> or force of nature that has </span>catastrophic consequences<span>, such as avalanche, earthquake, flood, forest fire, hurricane, lightning, tornado, tsunami and </span>
7 0
3 years ago
The stiffness of a particular spring is 42 N/m. One end of the spring is attached to a wall. A force of 2 N is required to hold
Liula [17]

Answer:

L_{o}=0.1224m

Explanation:

Given data

Force F=2 N

Length L=17 cm = 0.17 m

Spring Constant k=42 N/m

To find

Relaxed length of the spring

Solution

From Hooke's Law we know that

F_{spring}=k_{s}|s|\\F_{spring}=k_{s}(L-L_{o})\\ 2N=(42N/m)(0.17m-L_{o})\\2=7.14-42L_{o}\\-42L_{o}=2-7.14\\42L_{o}=5.14\\L_{o}=(5.14/42)\\L_{o}=0.1224m

6 0
3 years ago
A mass of 4kg suspended by a light string 2m long and at rest is projected horizontally with a velocity of 1.5 m/s. find the ang
Dafna11 [192]

Answer:

19.5°

Explanation:

The energy of the mass must be conserved. The energy is given by:

1) E=\frac{1}{2}mv^2+mgh

where m is the mass, v is the velocity and h is the hight of the mass.

Let the height at the lowest point of the be h=0, the energy of the mass will be:

2) E=\frac{1}{2}mv^2

The energy when the mass comes to a stop will be:

3) E=mgh

Setting equations 2 and 3 equal and solving for height h will give:

4) h=\frac{v^2}{2g}

The angle ∅ of the string with the vertical with the mass at the highest point will be given by:

5) cos\phi=\frac{l-h}{l}

where l is the lenght of the string.

Combining equations 4 and 5 and solving for ∅:

6) \phi={cos}^{-1}(\frac{l-h}{l})={cos}^{-1}(1-\frac{h}{l})={cos}^{-1}(1-\frac{v^2}{2gl})

8 0
3 years ago
the attendance qt a seminar in a year 1 was 500 in year 2 the attendance changed by 100 what was the percent change in attendanc
TiliK225 [7]
20% change from year one to year two.
5 0
3 years ago
Two parallel plates of area 7.34 x 10^-4 m^2 have 5.83 x 10^-8 C of charge placed on them. A 6.62 x 10^-6 C charge q1 is placed
inn [45]

Answer:

* if the two plates have the same charge sign       F_net = 0

*if one plate is positive and the other is negative   F_net = 59.4 N

Explanation:

The electric field created by a parallel plate is

           E = \frac { \sigma }{2 \epsilon_o  }

where sigma is the charge density

          σ = Q / A

we substitute

           E = \frac{Q}{A \ 2 \epsilon_o }

           E = \frac{ 5.83 \ 10^{-8} }{7.34 \ 10^{-4}\ 2 \ 8.5 \ 10^{-12} }

           E = 4.487 10⁶ N / C

the electric force is

          F = E / q

in this force it is a vector, so if the charges are of the same sign they repel and if they are of the opposite sign they attract. In this case, the test load is between the two plates that have the same load sign, so the forces are in the opposite direction.

* if the two plates have the same charge sign

          F_net = F₁ - F₂

          F_net = q (E₁ -E₂)

since the electric field does not depend on the distance

           E₁ = E₂

in consecuense  

           F_net = 0

In a more interesting case

*if one plate is positive and the other is negative

           F_net = F₁ + F₂

           F_net = q (E₁ + E₂) = 2 q E₁

           F_net = 2 6.62 10⁻⁶  4.487 10⁶

           F_net = 59.4 N

net force goes from positive to negative plate

7 0
3 years ago
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