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Delicious77 [7]
3 years ago
5

How many energy levels does uranium have?

Physics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

<u>Uranium</u> atoms have 92 <em>electrons</em> and the <u>shell structure</u> is 2.8.

Explanation:

<u>Classification:</u> <em>Uranium</em> is an actinide metal

<u>Protons:</u> 92

<u>Neutrons in most abundant isotope:</u> 146

<u>Electron shells:</u> 2,8,18,32,21,9,2

<u>Electron configuration:</u> [Rn] 5f3 6d1 7s2

<em>PLEASE MARK BRAINLIEST!</em>

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How many different values of l are possible for an electron with principal quantum number n=5?
lions [1.4K]

Answer:

different value to l if n=5 are 0,1,2,3,4

7 0
3 years ago
Kevin has a mass of 87 kg and is skating with in-line skates. He sees his 22-kg younger brother up ahead standing on the sidewal
neonofarm [45]

Answer:

V_ k = 3 m/s  

Explanation:

Using the conservation of the linear momentum P:

P_i = P_f

so:

M_kV_k = M_sV_s

where M_k is the mass of kevin, V_k is the velocity of kevin before he grabs her brother, M_s is the velocity of her brother and him after grabs her brother and V_s is the velocity of both after the collition.

So, replacing the values and solving for Vk, we get:

(87 kg)V_k = (87 kg+22 kg)(2.4m/s)

V_ k = 3 m/s

8 0
3 years ago
Energy in motion is _____ energy. potential scientific kinetic
Ket [755]

Answer:

kinetic energy

Explanation:

4 0
4 years ago
Read 2 more answers
In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w
Daniel [21]

Answer:

v_2=-133.17m/s, the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before (p_i) and after (p_f) the explosion. We will take the east direction as positive.

Before the explosion we have p_i=m_iv_i=Mv_i.

After the explosion we have pieces 1 and 2, so p_f=m_1v_1+m_2v_2.

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

Mv_i=m_1v_1+m_2v_2

Which means (since we want v_2 and M=m_1+m_2):

v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}

So for our values we have:

v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s

5 0
3 years ago
If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
4 years ago
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