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galina1969 [7]
3 years ago
14

Question 5 (1 point)

Physics
1 answer:
Tom [10]3 years ago
4 0

Answer: 18000 coulombs

Explanation:

Given that:

Current, I = 5.0A

Electric charge Q = ?

Time, T = 1 hour

(The SI unit of time is seconds. So, covert 1.0 hour to seconds)

If 1 hour = 60 minutes and 60 seconds = 1 minute

Then, 1.0 hour = (60 x 60)

= 3600 seconds

Since electric charge, Q = current x time

i.e Q = I x T

Q = 5.0 A x 3600 seconds

Q = 18000 coulombs

Thus, 18000 coulombs of charge flows through the lamp in this time.

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DanielleElmas [232]

Answer:

   t_total = 23.757 s

Explanation:

This is a kinematics exercise.

Let's start by calculating the distance and has to reach the limit speed of

v = 18.8 m / s

         v = v₀ + a t₁

the elevator starts with zero speed

         v = a t₁

         t₁ = v / a

         t₁ = 18.8 / 2.40

         t₁ = 7.833 s

in this time he runs

         y₁ = v₀ t₁ + ½ a t₁²

         y₁ = ½ a t₁²

         y₁ = ½ 2.40 7.833²

         y₁ = 73.627 m

This is the time and distance traveled until reaching the maximum speed, which will be constant throughout the rest of the trip.

           x_total = x₁ + x₂

           x₂ = x_total - x₁

           x₂ = 373 - 73,627

           x₂ = 299.373 m

this distance travels at constant speed,

           v = x₂ / t₂

           t₂ = x₂ / v

           t₂ = 299.373 / 18.8

           t₂ = 15.92 s

therefore the total travel time is

           t_total = t₁ + t₂

           t_total = 7.833 + 15.92

           t_total = 23.757 s

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