Answer:
The energy of photon is 20.22×10⁻¹⁷ J
Explanation:
Given data:
Frequency of photon = 3.05×10¹⁷ Hz
Energy of photon = ?
Solution:
Formula:
E = hf
h = planck's constant = 6.63×10⁻³⁴ Js
Now we will put the values in formula.
E = 6.63×10⁻³⁴ Js × 3.05×10¹⁷ Hz
Hz = s⁻¹
E = 20.22×10⁻¹⁷ J
Thus, the energy of photon is 20.22×10⁻¹⁷ J
Answer:
Explanation:
First, lets find the molar mass of CO². This is approximately 12 + 2(16) = 44 g/mol. Now, let's set up the conversions.
This is Avogadro's number
↓
243.6g CO² * (1 mol CO² /44g CO²) * (6.023 * 10^23 molecules/ 1 mol)
When we cancel out the units, we are left with 3.33 * 10^23 molecules of carbon dioxide. I hope this makes sense!
Answer : The hybridization of the positively charged carbon is .
Explanation : Formula used for Hybridization
Z=1/2{number of valence electrons of central atom + number of monovalent atom attached to it + negative charge - positive charge}
where, Z = Hybridization
Now for the compound
Number of valence electrons of central atom (C) = 4
Number of monovalent atom attached = 3
Number of negative charge = 0
Number of positive charge = 1
Now putting all the values in Z,
Z =
= 3
The corresponding Hybridization is i.e Trigonal planar .
Greetings!
The amount of a substance that can dissolve in a liquid (at a any temperature) is called the solubility of the substance, (in this case water).
<em>Hope this helps!</em>