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satela [25.4K]
4 years ago
7

A sample of water is mixed with a surfactant. What

Chemistry
2 answers:
jolli1 [7]4 years ago
5 0

Answer:

Surfactants reduce the surface tension of a liquid. The Most liklely thing to happen is that the viscosity of the water will decrease.

Ivahew [28]4 years ago
3 0

Answer:

The viscosity of the water will decrease.  Surfactants disrupt intermolecular forces within a liquid.  Viscosity is directly related to intermolecular forces.   If intermolecular forces are decreased, viscosity should also decrease.

have a good day ! :)

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A compound is made of 49.31% C, 43.79% 0 and the rest hydrogen. The molar
Alexeev081 [22]

Explanation:

49.31 + 43.79 = 93.10

finding the percentage of hydrogen in the compound hence 100-93.10 =6.9

therefore 6.9 percent of hydrogen is present in the compound

assuming that the compound is in 100 g so the elements present would be 49.31g of C , 43.79g of O and 6.9g of H

no. of moles of C = given mass÷molar mass

= 49.31 ÷ 12

=<em><u>4</u></em><em><u>.</u></em><em><u>1</u></em><em><u>1</u></em><em><u> </u></em><em><u>m</u></em><em><u>o</u></em><em><u>l</u></em>

no of moles of O = givem mass ÷molar mass

=43.79÷ 16

=<em><u>2</u></em><em><u>.</u></em><em><u>7</u></em><em><u>3</u></em><em><u> </u></em><em><u>m</u></em><em><u>o</u></em><em><u>l</u></em>

no. of moles of H =6.9÷1

=<em><u>6</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m</u></em><em><u>o</u></em><em><u>l</u></em>

dividing the no. of moles of each element by the least count of the elemnt to get the ratio of the simple whole numbr

therefore

so by dividing we get 1:1:2 of C:O:H

the empirical formula is CH2O

empirical formula mass of CH2O IS

= (12)+(2×1)+(16)

= 12+2+16

=30 G/MOL

n= molar mass of the compound ÷ empirical formula mass of the compound

so, n= 146.1 ÷30

n=5

molecular formula = n×empirical formula

<em>m</em><em>o</em><em>l</em><em>e</em><em>c</em><em>u</em><em>l</em><em>a</em><em>r</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em>=</em><em> </em><em>5</em><em>×</em><em>C</em><em>H</em><em>2</em><em>O</em>

<em>m</em><em>o</em><em>l</em><em>e</em><em>c</em><em>u</em><em>l</em><em>a</em><em>r</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em>=</em><em>C</em><em>5</em><em>H</em><em>1</em><em>0</em><em>O</em><em>5</em><em> </em><em>(</em><em>r</em><em>i</em><em>b</em><em>o</em><em>s</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>m</em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em>)</em>

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ELEN [110]

Answer:

Reactants break bonds with consuming the energy and form the new bonds .

Explanation:

As the two molecules interacted with each other , the elements reshuffled the bonds and formed the new ones with shifting the energy and converting it into new products .

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The free energy obtained from the oxidation (reaction with oxygen) of glucose (C6H12O6) to form carbon dioxide and water can be
babunello [35]

Answer:

The correct answer is -2878 kJ/mol.

Explanation:

The reaction that takes place at the time of the oxidation of glucose is,  

C₆H₁₂O₆ (s) + 6O₂ (g) ⇒ 6CO₂ (g) + 6H₂O (l)

The standard free energy change for the oxidation of glucose can be determined by using the formula,  

ΔG°rxn = ∑nΔG°f (products) - ∑nΔG°f (reactants)

The ΔG°f for glucose is -910.56 kJ/mol, for oxygen is 0 kJ/mol, for H2O -237.14 kJ/mol and for CO2 is -394.39 kJ/mol.  

Therefore, ΔG°rxn = 6 (-237.14) + 6 (-394.39) - (-910.56)

ΔG°rxn = -2878 kJ/mol

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How many atoms of iron are in one formula unit of iron (III) chloride
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FeC13=1 atom of Fe, 3 atoms of CI
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4 years ago
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What is the hypothesis
Ulleksa [173]
A hypothesis is an educated guess, most likely in an "If... and then..." statement.
So, this paper is asking you to make a hypothesis about this experiment?
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