Answer:
0.182 m/s
Explanation:
m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s
let the velocity of loaded freight car is v
Use the conservation of momentum
m1 x u1 + m2 x 0 = (m1 + m2) x v
30,000 x 0.85 = (30,000 + 110,000) x v
v = 0.182 m/s
GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N
<span>GPE=mgh=675(26000)=17.55x10^6J</span>
Answer:
M1 = 16.9 mA
M2 = 0 A
Explanation:
As the ratio of the two sets of series resistors is almost exactly identical, there is no voltage difference across M2 to cause current flow
269/(269 + 439) = 0.3799...
500/(500 + 815) = 0.38022
M2 = 0
M1 sees only the current flowing through the far left resistors in series
A = V/R = 12/(269 + 439) = 0.016949... ≈ 16.9 mA
