EC_1 + EP_1 = EC2 + EP_2
EC_2 = 0
EC_2 = EP_1 - EP_2
EC_2 = mg(H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
Weight is equivalent to the product of the mass of an object and the strength of the gravitational field.
Using:
F = ma
a = 8.2 / 5
a = 1.64 N/kg
The gravitational field strength is equivalent to 1.64 N/kg.
To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.
E concave mirror because it reflects the light
If <em>v(t)</em> is speed measured in meters per second (m/s), and <em>t</em> is time measured in seconds (s), then the constants <em>A</em> and <em>B</em> in
<em>v(t)</em> = <em>At</em> ³ - <em>Bt</em>
must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.
[m/s] = <em>A</em> [s]³ - <em>B</em> [s]
[m/s] = [m/s⁴] [s]³ - [m/s²] [s]
[m/s] = [m/s] - [m/s]
[m/s] = [m/s]
